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emmainna [20.7K]
2 years ago
7

Pls help in a middle of an exam

Mathematics
1 answer:
KIM [24]2 years ago
3 0

Answer:

\frac{2x^2+4x-9}{(2x-3)(2x+3)(x-1)}

Step-by-step explanation:

\frac{2x}{4x^2-9} + \frac{3}{2x^2+x-3} can be simplified to:
\frac{2x}{(2x-3)(2x+3)}+\frac{3}{(2x+3)(x-1)}

Make them have common denominators so:
\frac{(2x)(x-1) +3(2x-3)}{(2x-3)(2x+3)(x-1)}

Simplify:
\frac{2x^2-2x+6x-9}{(2x-3)(2x+3)(x-1)} = \frac{2x^2+4x-9}{(2x-3)(2x+3)(x-1)}

I don't think you can simplify that fraction further so that's the answer.

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