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Tems11 [23]
3 years ago
15

1.) The length of the missing side is? 2.) What is the length of the missing side?

Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0
To find the hypotenuse the formula would be:

c^2 = a^2 + b^2

BUT! These two questions ask for the length of the smaller sides, so we need to rearrange the formula to:

a^2 = c^2 - b^2

Where c is the hypotenuse, and b is the other known length. Use this formula to solve the length of the unknown side. 

Let's call the unknown side x,

1) a^2 = c^2 - b^2
    x^2 = 17^2 - 15^2
    x^2 = 64
    Square root both sides to get x
    x = 8

2) a^2 = c^2 - b^2
    x^2 = 26^2 - 24^2
    x^2 = 100
    Square root both sides to get x
    x = 10

Hope this helped! Ask me if there's any part of the working you don't understand :)
koban [17]3 years ago
6 0
A^2 + b^2 = c^2
a^2 + 15^2 = 17^2
a^2 + 225 = 289
a^2 = 289 - 225
a^2 = 64
sqrt of 64 = 8
a = 8
x = 8
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Plz help me with this math question
sergejj [24]

Answer:

8^2-60 ,   11^1   , 2^2x5

Step-by-step explanation:

2^2= 4

4 x 5 = 20

11^1= 11

8^2= 64

64-60 = 4

5 0
3 years ago
The difference between twice a number, x, and a smaller number, y, is 3. The sum of twice the number and the smaller number is-3
sasho [114]
A. y= 2x - 3 and y= -2x - 3
4 0
4 years ago
Read 2 more answers
Answer all 3 for brainliest
fiasKO [112]

Answer:

7.) 53.38

8.) 18.84

9.) 87.92

Step-by-step explanation:

7.)

For the first question, we can see that the diameter is given. So, we will want to divide that diameter by 2 to get the radius. 17 ÷ 2 = 8.5.

The formula for finding the circumference is 2 × π × 8.5

2 × 3.14(π) = 6.28.

6.28 × 8.5 = 53.38

8.)

For the second question, we can see that the radius is now given to us which is 3ft.

The formula for finding the circumference is 2 × π × 3

2 × 3.14(π) = 6.28.

6.28 × 3 = 18.84

9.)

For the third question the raduis is also given to us, which is 14 in.

The formula for finding the circumference is 2 × π × 14.

2 × 3.14(π) = 6.28.

6.28 × 14 = 87.92

<em>-kiniwih426</em>

7 0
3 years ago
How many whole numbers are there, whose squares and cubes have the same number of digits?
Naddik [55]

Answer:

there are only 4 whole numbers whose squares and cubes have the same number of digits.

Explanations:

let 0, 1, 2 and 4∈W (where W is a whole number), then

0^2=0, 0^3=0,

1^2=1, 1^3=1,

2^2=4, 2^3=8,

4^2=16, 4^3=64.

You can see from the above that only four whole numbers are there whose squares and cubes have the same number of digits







7 0
3 years ago
In quadrant 11 and if x=-3/2 what is y ?
Ratling [72]
It’s 3 bbbbbbbbbbbbbbbbbbbb
5 0
3 years ago
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