If you take the derivative of your equation, you get:
2′″−″−′+′=0
2
y
′
y
″
−
x
y
″
−
y
′
+
y
′
=
0
or
″(2′−)=0.
y
″
(
2
y
′
−
x
)
=
0.
Let =′
v
=
y
′
and we have ′(2−)=0,
v
′
(
2
v
−
x
)
=
0
,
so either ′=0
v
′
=
0
and =
v
=
c
or =/2
v
=
x
/
2
.
Then ′=
y
′
=
c
and so =+
y
=
c
x
+
d
or ′=/2
y
′
=
x
/
2
and =2/4.
y
=
x
2
/
4.
Plugging the first into the original equation gives =−2
d
=
−
c
2
. So there are two solutions =−2
y
=
c
x
−
c
2
for some constant
c
and =2/4
y
=
x
2
/
4
. I don't know if this is all the solutions
Answer:
x = 6
Step-by-step explanation:
f(x) = 2(x + 4)
Let f(x) =20
20 = 2(x + 4)
Divide by 2
20/2 = 2/2 (x+4)
10 = x+4
Subtract 4 from each side
10-4 =x+4-4
6 =x
Answer:
18 million kilometers in one min. and 0.3 million kilometers in one second
Step-by-step explanation:
so the one min. is easy because all you have to do is take 180 and divide it by 10 and you get 18 million kilometers in one min. and then you would take 18 and divide it by 60 and you would get 0.3 million kilometers in one second
The permutation illustrates that if no one has been cast yet, the different ways that are there to cast Jean Valjean from the 22 men is 22.
<h3>How to compute the value?</h3>
The ways to cast Jean will be:
= 22!/(22 - 1)!
= 22!/21!
= 22
When Jean Valjean has already been cast, the different ways that are there to cast Inspector Javert from the remaining men will be:
= 21!/(21 - 1)!
= 21!/20!
= 21
When Jean Valjean and Inspector Javert have already been cast, the different ways that are there to cast Marius from the remaining men will be:
= 20!/(20 - 1)!
= 20!/19!
= 20
Learn more about permutations on:
brainly.com/question/4658834
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