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neonofarm [45]
2 years ago
11

If you were hunter and your father was a hunter, this is known as

Social Studies
1 answer:
lianna [129]2 years ago
6 0
It is known as hunter x hunter
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Changing how clients ______________ old problematic relational patterns in their current interactions with family members is a p
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Clients ought to know how to respond to old problematic relational patterns in their interaction with their families. Their response or how they respond during this shows that they are growing

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Erik erikson's fourth stage of development, appearing during middle and late childhood, is called:
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Industry (competence) vs. Inferiority
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What lines run from the top to bottom, through the North and South poles?
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The lines that run from the top to bottom through the North and South poles is called the Prime Meridian.
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With regard to personality assessment methods, supporters of the ____________ test claim that responses from the assessment can
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With regard to personality assessment methods, supporters of the Rorschach inkblot test claim that responses from the assessment can help them diagnose various psychological disorders, such as depression, suicidal thoughts, pedophilia, post-traumatic stress disorder, or anxiety disorders.

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Suppose you find a rock that contains 10 micrograms of radioactive potassium-40, which has a half-life of 1.25 billion years. By
attashe74 [19]

Answer:

The rock is 3.75 billion years ago.

Explanation:

Given that:

Half life = 1.25 billion years

1 billion years = 10⁹ years

So,

Half life = 1.25 × 10⁹ years

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{1.25\times 10^9}\ year^{-1}

The rate constant, k = 5.5452 × 10⁻¹⁰ years⁻¹

Initial amount [A₀] = 80 micrograms

Final amount [A_t] = 10 micrograms

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

So,  

10=80\times e^{-5.5452\times 10^{-10}\times t}

80e^{-5.5452\times \:10^{-10}x}=10

\frac{80e^{-5.5452\times \:10^{-10}x}}{80}=\frac{10}{80}

\ln \left(e^{-5.5452\times \:10^{-10}x}\right)=\ln \left(\frac{1}{8}\right)

x=\frac{10^{10}\times \:3\ln \left(2\right)}{5.5452}=3.75\times 10^9

So,

<u>The rock is 3.75 billion years ago.</u>

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