For a better understanding of the explanation provided here kindly go through the file attached.
Since, the weight attached is already at the lowest point at time, t=0, therefore, the equation will have a -9 as it's "amplitude" and it will be a Cosine function. This is because in cosine function, the function has the value of the amplitude at t=0.
Now, we know that the total angle in radians covered by a cosine in a given period is
and the period given in the question is t=3 seconds. Therefore, the angular velocity,
of the mentioned system will be:

Combining all the above information, we see that the equation which models the distance, d, of the weight from its equilibrium after t seconds will be:

Thus, Option B is the correct option. The attached diagram is the graph of the option B and we can see clearly that at t=3, the weight indeed returns to it's original position.
Answer:
yes because radius makes 90 degree with it. using Pythagoras theorem, it is seen that 5^2 = 3^2 + 4^2
Answer:
A. The graph of the function increases and decreases over its domain.
Step-by-step explanation:
The graph is attached. Some places, it has positive slope (is increasing); other places it has negative slope (is decreasing).
㏒₂(5x + 3) = 3
2³ = 5x + 3 Cange the equation.
8 = 5x + 3 Multiphy 2 by itself three times.
- 3 - 3 Subtract 3 from each side.
5 = 5x
5 5 Divide it by 5
1 = x Find the answer.