Answer:
70.7 meters.
Step-by-step explanation:
We have been given that Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters.
Since we know that diagonal of a square is product of side length of square and
. So we will find diagonal of our given square plaza by multiplying 50 by
.
![\text{Diagonal distance across the plaza}=50\times \sqrt{2}](https://tex.z-dn.net/?f=%5Ctext%7BDiagonal%20distance%20across%20the%20plaza%7D%3D50%5Ctimes%20%5Csqrt%7B2%7D)
![\text{Diagonal distance across the plaza}=50\times 1.414213562373095](https://tex.z-dn.net/?f=%5Ctext%7BDiagonal%20distance%20across%20the%20plaza%7D%3D50%5Ctimes%201.414213562373095)
![\text{Diagonal distance across the plaza}=70.71067811865475\approx 70.7](https://tex.z-dn.net/?f=%5Ctext%7BDiagonal%20distance%20across%20the%20plaza%7D%3D70.71067811865475%5Capprox%2070.7)
Therefore, diagonal distance across the plaza is 70.7 meters.
Answer:
a: -1/7
b: 1/2
c: -1
d: none
Step-by-step explanation:
9514 1404 393
Answer:
cot(θ) = 4/5
Step-by-step explanation:
In the polar/rectangular coordinate representation (x, y) ⇔ (r; θ), we know that ...
(x, y) = (r·cos(θ), r·sin(θ))
From the various trig definitions and identities, we also know that ...
cot(θ) = cos(θ)/sin(θ) = (x/r)/(y/r) = x/y
For the given (x, y) = (-4, -5), the cotangent is ...
cot(θ) = -4/-5 = 4/5
The distance traveled reported too high.
<h3>More</h3>
![\boxed{\sf Average \:Speed=\dfrac{Total\:Distance}{Total\:Time}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20Average%20%5C%3ASpeed%3D%5Cdfrac%7BTotal%5C%3ADistance%7D%7BTotal%5C%3ATime%7D%7D)
It has SI units m/s