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1 year ago

Find the real solutions of the equation by graphing. x^3-4x^2-20x=-48The real solutions of the equation are _____.

Mathematics

1 answer:

AnnZ [28]1 year ago

7 0

Given the following equation:

$x^3-4x^2-20x=-48$

We will find the real solutions to the equation by graphing.

We will rewrite the given equation as follows:

$x^3-4x^2-20x+48=0$

The graph of the function will be as shown in the following figure:

As shown the function has 3 real solutions which are the x-intercepts

So, the answer will be:

$x=-4,2,6$

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Multiply or divide as indicated. Y^-9•y^-8•y^10

BabaBlast [244]

Answer:

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Step-by-step explanation:

Y^-9•y^-8•y^10

= y^10 / y^9•y^8

= y^10 / y^17

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3 years ago

Write 3x-7+2(2x-7) as the product of 7 and another factor

tankabanditka [31]

Answer:

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Step-by-step explanation:

Given

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= 7x - 21 ← factor out 7 from each term

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3 years ago

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

s344n2d4d5 [400]

From the first equation
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3 years ago

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Blizzard [7]

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3 years ago

Read 2 more answers

Add and subtract rational numbers without common denominators. Show work! 1. 7/4 - 3/2 - 2/5 = 2. - 5/16 + 3/4 + 1/8 = 3. 3/4 -

alukav5142 [94]

$\dfrac{7}{4} - \dfrac{3}{2} - \dfrac{2}{5}$

$= \dfrac{7 \times 5}{4 \times 5} - \dfrac{3 \times 10}{2 \times 10} - \dfrac{2 \times 4}{5 \times 4}$

$= \dfrac{35}{20} - \dfrac{30}{20} - \dfrac{8}{20}$

$= \dfrac{35-30-8}{20}$

$= \dfrac{3}{20}$

---------------------------------------------------------------

$-\dfrac{5}{16} + \dfrac{3}{4} + \dfrac{1}{8}$

$= -\dfrac{5}{16} + \dfrac{3 \times 4}{4 \times 4} + \dfrac{1 \times 2}{8 \times 2}$

$= -\dfrac{5}{16} + \dfrac{12}{16} + \dfrac{2}{16}$

$= \dfrac{-5+ 12 + 2}{16}$

$= \dfrac{9}{16}$

---------------------------------------------------------------

$\dfrac{3}{4} - \dfrac{1}{3} - \dfrac{7}{12}$

$= \dfrac{3 \times 3}{4 \times 3} - \dfrac{1 \times 4}{3 \times 4} - \dfrac{7}{12}$

$= \dfrac{9}{12} - \dfrac{4}{12} - \dfrac{7}{12}$

$= \dfrac{9 - 4 - 7}{12}$

$= -\dfrac{2}{12}$

$= -\dfrac{1}{6}$

---------------------------------------------------------------

$\dfrac{2}{9} - \dfrac{2}{12} - \dfrac{2}{3}$

$= \dfrac{2}{9} - \dfrac{1}{6} - \dfrac{2}{3}$

$= \dfrac{2 \times 2}{9 \times 2} - \dfrac{1 \times 3}{6 \times 3} - \dfrac{2 \times 6}{3 \times 6}$

$= \dfrac{4}{18} - \dfrac{3}{18} - \dfrac{12}{18}$

$= \dfrac{4 - 3 - 12}{18}$

$= - \dfrac{11}{18}$

6 0

3 years ago