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pickupchik [31]
2 years ago
13

Which choice is equivalent to the quotient below? √64/√4a. √2b. √4/4c. √8/2d. 4​

Mathematics
1 answer:
Ksju [112]2 years ago
4 0

Step-by-step explanation:

you did not even try a calculator to find the result ?

64 is 8×8 or 8².

so, sqrt(64) = 8.

similarly for 4 :

4 is 2×2 or 2².

so, sqrt(4) = 2

so,

sqrt(64)/ sqrt(4) = 8 / 2 = 4

so, d. is the right answer.

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Is the following function even, odd, or neither?<br> 1<br> 4 – 22
olga2289 [7]

Answer:

I would think neither after graphing it. Sorry if i'm wrong.

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Y = (x) = (1/9)^x<br> Find f(x) when x = (1/2)<br> Round your answer to the nearest thousandth.
irina [24]

Answer:

0.333

Step-by-step explanation:

6 0
3 years ago
The number represented by x is less than 7 and is evenly divisible by both 0.6 and 2.4
svetoff [14.1K]
2.4<7
2.4 / 0.6 = 4
2.4 / 2.4 = 1

4.8<7
4.8 / 0.6 = 8
4.8 / 2.4 = 2

6 0
3 years ago
After being rearranged and simplified, which of the following equations could
masha68 [24]

Answer:

C and D

Step-by-step explanation:

The quadratic formula is

x= (-b±√b²-4ac)/2a

The formula uses the numerical coefficients in the quadratic equation.

The general quadratic equation is ax²+bx+c where a, b and c are the numerical coefficients

So, lets try and see;

A.

5x+4=3x^4-2\\\\=3x^4-5x-2-4\\=3x^4-5x-6\\a=3,b=-5,c=-6

But due to the fact that  in this equation you have x⁴, the equation is not a quadratic equation thus can not be solved using this formula

B

-x^2+4x+7=-x^2-9\\\\\\=-x^2+x^2+4x+7+9\\=4x+16

C

9x+3x^2=14+x-1\\\\\\=3x^2+9x-x-14+1\\\\=3x^2+8x-13\\\\\\a=3,b=8,c=-13\\

D.

2x^2+x^2+x=30\\\\\\=3x^2+x-30\\\\\\a=3,b=1,c=-30

From the checking above, the equations will be C and D

7 0
3 years ago
Read 2 more answers
Look at the attached file. <br><br> please show your work on how you got the answer
statuscvo [17]

Answer:

D

Step-by-step explanation:

\frac{f(x)}{g(x)}

= \frac{2x+4}{2x^2+4x}

Factor out 2 on the numerator and 2x on the denominator.

= \frac{2(x+2)}{2x(x+2)}

Cancel the factor (x + 2) on the numerator/ denominator

= \frac{2}{2x} ← cancel the 2 on numerator/ denominator

= \frac{1}{x} : x ≠ 0

8 0
3 years ago
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