Question

Look at the attached file. please show your work on how you got the answer

Answer 1

Answer:

D

Step-by-step explanation:

$\frac{f(x)}{g(x)}$

= $\frac{2x+4}{2x^2+4x}$

Factor out 2 on the numerator and 2x on the denominator.

= $\frac{2(x+2)}{2x(x+2)}$

Cancel the factor (x + 2) on the numerator/ denominator

= $\frac{2}{2x}$ ← cancel the 2 on numerator/ denominator

= $\frac{1}{x}$ : x ≠ 0