You have to make 7 into 21/3. Then change 2 1/3 into 7/3. Then divide 21/3 abd 7/3 which equals 3/3 which equals 1.
Find the area of the parallelogram, find the area of the triangle, then subtract the triangle's area from the area of the parallelogram.
Area of Parallelogram:
A= base * height
A= 20 in * 10 in
A= 200 in^2
Area of Triangle:
A= 1/2 base * height
A= 1/2 (10 in)(9 in)
A= 1/2 (90)
A= 45 in ^2
Area of Poster Left:
subtract the difference
A= Parallelogram Area - Triangle Area
A= 200 in^2 - 45 in^2
A= 155 in^2
ANSWER: 155 in^2 is the area of the poster board she has left.
Hope this helps! :)
Well, remember
(ab)(cd)=abcd=(ac)(bd)
so
(8t^5)(8t^5)=(8)(t^5)(8)(t^5)=(8*8)(t^5*t^5)=64t^10