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3 years ago

Find the measure of angle A. 71° x+49 +72

Mathematics

1 answer:

slega [8]3 years ago

5 0

Answer: 66 degrees

Step-by-step explanation:

Sum of the angle measures is 180, so:

71 + x + 49 + x + 72 = 180

2x + 192 = 180

2x = -12

x = -6

Meaning the measure of angle A = -6 + 72 = 66 deg.

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What is 7/10 + 7/10 =

Nonamiya [84]

The correct answer is 1.4 or 1 4/10

I did this by turning 7/10 into a decimal which is 0.7.

Now I just add 0.7 + 0.7.

For that equation i got 1.4

This would equal 1 4/10

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Greastest common factor of 24 and 18

Vilka [71]

Answer: 6

Step-by-step explanation:

the biggest number that can go into both 24 and 18 evenly is 6. 24/6 is four, and 18/6 is three

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Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26

LiRa [457]

we know that

A polynomial in the form $a^{3}-b^{3}$ is called adifference of cubes. Both terms must be a perfect cubes

Let's verify each case to determine the solution to the problem

case A) $9w^{33} -y^{12}$

we know that

$9=3^{2}$ ------> the term is not a perfect cube

$w^{33}=(w^{11})^{3}$ ------> the term is a perfect cube

$y^{12}=(y^{4})^{3}$ ------> the term is a perfect cube

therefore

The expression $9w^{33} -y^{12}$ is not a difference of cubes because the term $9$ is not a perfect cube

case B) $18p^{15} -q^{21}$

we know that

$18=2*3^{2}$ ------> the term is not a perfect cube

$p^{15}=(p^{5})^{3}$ ------> the term is a perfect cube

$q^{21}=(q^{7})^{3}$ ------> the term is a perfect cube

therefore

The expression $18p^{15} -q^{21}$ is not a difference of cubes because the term $18$ is not a perfect cube

case C) $36a^{22} -b^{16}$

we know that

$36=2^{2}*3^{2}$ ------> the term is not a perfect cube

$a^{22}$ ------> the term is not a perfect cube

$b^{16}$ ------> the term is not a perfect cube

therefore

The expression $36a^{22} -b^{16}$ is not a difference of cubes because all terms are not perfect cubes

case D) $64c^{15} -a^{26}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$a^{26}$ ------> the term is not a perfect cube

therefore

The expression $64c^{15} -a^{26}$ is not a difference of cubes because the term $a^{26}$ is not a perfect cube

I'm adding a new case so I can better explain the problem

case E) $64c^{15} -d^{27}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$d^{27}=(d^{9})^{3}$ ------> the term is a perfect cube

Substitute

$64c^{15} -d^{27}=((2^{2})(c^{5}))^{3}-(d^{9})^{3}$

therefore

The expression $64c^{15} -d^{27}$ is a difference of cubes because all terms are perfect cubes

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3 years ago

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victus00 [196]

Answer:

Your answer is 5/18

Step by step Explanation:

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When we divide it becomes reverse so, 

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makkiz [27]

Answer: 27a^3

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