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just olya [345]
3 years ago
10

Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26

Mathematics
2 answers:
LiRa [457]3 years ago
5 0

we know that

A polynomial in the form a^{3}-b^{3} is called adifference of cubes. Both terms must be a perfect cubes

Let's verify each case to determine the solution to the problem

<u>case A)</u> 9w^{33} -y^{12}

we know that

9=3^{2} ------> <u>the term is not a perfect cube</u>

w^{33}=(w^{11})^{3} ------> the term is a perfect cube

y^{12}=(y^{4})^{3} ------> the term is a perfect cube

therefore

The expression 9w^{33} -y^{12} is not a difference of cubes because the term 9 is not a perfect cube

<u>case B)</u> 18p^{15} -q^{21}  

we know that

18=2*3^{2} ------> <u>the term is not a perfect cube</u>

p^{15}=(p^{5})^{3} ------> the term is a perfect cube

q^{21}=(q^{7})^{3} ------> the term is a perfect cube

therefore

The expression 18p^{15} -q^{21} is not a difference of cubes because the term 18 is not a perfect cube

<u>case C)</u> 36a^{22} -b^{16}

we know that

36=2^{2}*3^{2} ------> <u>the term is not a perfect cube</u>

a^{22} ------>  <u>the term is not a perfect cube</u>

b^{16} ------> <u>the term is not a perfect cube</u>

therefore

The expression 36a^{22} -b^{16} is not a difference of cubes because all terms are not perfect cubes

<u>case D)</u> 64c^{15} -a^{26}

we know that

64=2^{6}=(2^{2})^{3} ------>  the term is a perfect cube

c^{15}=(c^{5})^{3} ------>   the term is a perfect cube

a^{26} ------> <u>the term is not a perfect cube</u>

therefore

The expression 64c^{15} -a^{26} is not a difference of cubes because the term a^{26} is not a perfect cube

I'm adding a new case so I can better explain the problem

<u>case E)</u> 64c^{15} -d^{27}

we know that

64=2^{6}=(2^{2})^{3} ------>  the term is a perfect cube

c^{15}=(c^{5})^{3} ------>   the term is a perfect cube

d^{27}=(d^{9})^{3} ------>  the term is a perfect cube

Substitute

64c^{15} -d^{27}=((2^{2})(c^{5}))^{3}-(d^{9})^{3}

therefore

The expression 64c^{15} -d^{27} is a difference of cubes because all terms are perfect cubes



tigry1 [53]3 years ago
3 0

The expression \boxed{64{c^{15}} - {d^{27}}} is a difference of cubes.

Further Explanation:

Given:

The options are as follows,

(a). 9{w^{33}} - {y^{12}}

(b). 18{p^{15}} - {q^{21}}

(c). 36{a^{22}} - {b^{16}}

(d). 64{c^{15}} - {a^{26}}

(e). 64{c^{15}} - {d^{27}}

Calculation:

The cubic formula can be expressed as follows,

\boxed{{a^3} + {b^3} = \left( {a + b} \right)\left( {{a^2} - ab + {b^2}} \right)}

The expression is 9{w^{33}} - {y^{12}}.

9 is not a perfect cube of any number,{w^{33}} can be written as {\left( {{w^{11}}} \right)^3} and {y^{12}} can be represents as {\left( {{y^4}} \right)^3}.

9{w^{33}} - {y^{12}}cannot be written as the difference of cube. Option (a) is not correct.

The expression is 18{p^{15}} - {q^{21}}.

18 is not a perfect cube of any number, {p^{15}} can be written as {\left( {{p^5}} \right)^3} and {q^{21}} can be written as {\left( {{q^7}} \right)^3}.

18{p^{15}} - {q^{21}} cannot be written as the difference of cube. Option (b) is not correct.

The expression is 36{a^{22}} - {b^{16}}.

36 is not a perfect cube of any number, {a^{22}} is not perfect cube and {b^{16}} is not a perfect cube.

36{a^{22}} - {b^{16}} cannot be written as the difference of cube. Option (c) is not correct.

The expression is 64{c^{15}} - {a^{26}}.

64 can be written as {\left( {{2^2}} \right)^3}, {a^{26}} is not perfect cube and {c^{15}} can be written as {\left( {{c^5}} \right)^3}.

64{c^{15}} - {a^{26}} cannot be written as the difference of cube. Option (d) is not correct.

The expression is 64{c^{15}} - {d^{27}}.

64 can be written as {\left( {{2^2}} \right)^3}, {d^{27}} can be written as {\left( {{d^9}} \right)^3} and {c^{15}} can be written as {\left( {{c^5}} \right)^3}.

\boxed{64{c^{15}} - {d^{27}} = {{\left( {{2^2}{c^5}} \right)}^3} - {{\left( {{d^9}} \right)}^3}}

64{c^{15}} - {d^{27}} can be written as the difference of cube. Option (e) is correct.

The expression \boxed{64{c^{15}} - {d^{27}}} is a difference of cubes.

Learn more:

1. Learn more about unit conversion brainly.com/question/4837736

2. Learn more about non-collinear brainly.com/question/4165000

3. Learn more aboutbinomial and trinomial brainly.com/question/1394854

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Exponents and Powers

Keywords: Solution, factorized form, expression, difference of cubes, exponents, power, equation, power rule, exponent rule.

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