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3 years ago

A baker is folding up open-topped boxes to package up her baked goods. She has

Mathematics

1 answer:

Brrunno [24]3 years ago

4 0

Answer:

She should cut 1.21 inches (or a square of area 1.46 inch²) from 4 corners to get the maximum volume

Step-by-step explanation:

Length = L = 10 inches

Width = W = 6 inches

Suppose x is cut from the 4 corners to make a box.

Dimensions of the Box:

L= 10 - 2x

W = 6 - 2x

H = x

Volume of the Box:

V = (L)(W)(H)

V = (10-2x)(6-2x)(x)

V = 4x³ - 32x² + 60x

For Maximum value:

$\frac{dV}{dx}=0$

$\frac{dV}{dx}=\frac{d}{dx}(4x^3-32x+60x)\\\frac{dV}{dx}=12x^2-64x+60\\12x^2-64x+60 = 0$

The values of x found are:

x= 4.12 , x = 1.21

If we put x= 4.12 in W= 6-2x , the value of width becomes negative, so that is not possible.

We discard 4.12. Now x=1.21

So,

If 1.21 inches are cut from 4 corners, or a square of 1.21*1.21 = 1.46 inch² is cut from 4 corners, we get the maximum value of V

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Marigold Industries collected $104,000 from customers in 2019. Of the amount collected, $24,400 was for services performed in 20

m_a_m_a [10]

Answer:

$\text{Net accrual income}=\$31,600$

Step-by-step explanation:

We have been given that Marigold Industries collected $104,000 from customers in 2019. Of the amount collected, $24,400 was for services performed in 2018. In addition, Marigold performed services worth $39,000 in 2019, which will not be collected until 2020.

Let us find revenue earned in 2019 by subtracting revenue earned from 2018 and adding revenue earned in 2019 to total revenue as:

$\text{Revenue in 2019}=\$104,000-\$24,400+\$39,000$

$\text{Revenue in 2019}=\$118,600$

Marigold Industries also paid $73,900 for expenses in 2019. Of the amount paid, $29,100 was for expenses incurred on account in 2018. In addition, Marigold incurred $42,200 of expenses in 2019, which will not be paid until 2020.

Now, we will find expenses in 2019 by subtracting expenses in 2018 and adding expenses in 2019 to total expenses as:

$\text{Expenses in 2019}=\$73,900-\$29,100+\$42,200$

$\text{Expenses in 2019}=\$87,000$

To find accrual net-income, we will subtract$87,000 from $118,600 as:

$\text{Net accrual income}=\$118,600-\$87,000$

$\text{Net accrual income}=\$31,600$

Therefore, the net accrual income for 2019 would be $31,600.

5 0

2 years ago

A state lottery sells instant-lottery scratch tickets. 12% of the tickets have prizes. Neil goes to the store and buys 10 ticket

Readme [11.4K]

Answer:

The probability of success is .12

The probability of failure is .88

According to the binomial theorem the probability of 3 success is

10! / (3! * 7!) * .12^3 * .88^7 = .085

5 0

2 years ago

I need help on these what is 5=g-8

Levart [38]

The answer is g=13 I hope this helped

7 0

3 years ago

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian

Alla [95]

Answer: mass (m) = 4 kg

center of mass coordinate: (15.75,4.5)

Step-by-step explanation: As a surface, a lamina has 2 dimensions (x,y) and a density function.

The region D is shown in the attachment.

From the image of the triangle, lamina is limited at x-axis: 0≤x≤2

At y-axis, it is limited by the lines formed between (0,0) and (2,1) and (2,1) and (0.3):

Points (0,0) and (2,1):

y = $\frac{1-0}{2-0}(x-0)$

y = $\frac{x}{2}$

Points (2,1) and (0,3):

y = $\frac{3-1}{0-2}(x-0) + 3$

y = -x + 3

Now, find total mass, which is given by the formula:

$m = \int\limits^a_b {\int\limits^a_b {\rho(x,y)} \, dA }$

Calculating for the limits above:

$m = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2(x+y)} \, dy \, dx }$

where a = -x+3

$m = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {(xy+\frac{y^{2}}{2} )} \, dx }$

$m = 2.\int\limits^2_0 {(-x^{2}-\frac{x^{2}}{2}+3x )} \, dx }$

$m = 2.\int\limits^2_0 {(\frac{-3x^{2}}{2}+3x)} \, dx }$

$m = 2.(\frac{-3.2^{2}}{2}+3.2-0)$

m = 2(-4+6)

m = 4

Mass of the lamina that occupies region D is 4.

Center of mass is the point of gravity of an object if it is in an uniform gravitational field. For the lamina, or any other 2 dimensional object, center of mass is calculated by:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$