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FinnZ [79.3K]
2 years ago
11

The box plots display the same data for the number of crackers in each snack bag, but one includes the outlier in the data and t

he other excludes it. 4, 14, 15, 15, 16, 16, 18, 19, 20, 20, 21 number of crackers in each bag, with outlier a number line goes from 0 to 26. the whiskers range from 4 to 21, and the box ranges from 15 to 20. a line divides the box at 16. number of crackers in each bag, without outlier a number line goes from 0 to 26. the whiskers range from 14 to 21, and the box ranges from 15 to 20. a line divides the box at 17. which statement comparing the box plots is true? both the median and the range changed. both the range and the lower quartile changed. both the median and the interquartile range changed. both the interquartile range and the lower quartile changed.
Mathematics
1 answer:
Murljashka [212]2 years ago
3 0

Both the median and the range changed, the correct option is A.

<h3>What is the median?</h3>

Median, in statistics, is the middle value of the given list of data, when arranged in an order.

The data set that contains the outlier is given as:

4, 14, 15, 15, 16, 16, 18, 19, 20, 20, 21

The minimum value of the data is: 4

The median or middle quartile i.e. \rm Q_2  is the central tendency of the data and exists in the middle of the data.

The median is: 16

Also, the lower set of data is:

4,14,15,15,16

The lower quartile i.e. \rm Q_1  is the median of the lower set of data.

The  lower quartile i.e. \rm Q_1 = 15

Similarly, the upper set of data is:

18, 19, 20, 20, 21

the upper quartile i.e. \rm Q_3  is the median of the upper set of data.

upper quartile i.e. \rm Q_3 = 20

Also, the interquartile range is:

\rm Q_3-Q_1=20-15=5

The maximum value of the set is 21.

Range = Maximum value-Minimum value =21 - 4 = 17

As we know that 4 is the outlier of the data as it is the smallest as compared to all the data points.

After removing the outlier the data set is:

14, 15, 15, 16, 16, 18, 19, 20, 20, 21

The minimum value of the set =14

The maximum value of set =21

Range = Maximum value-Minimum value =21-14 = 7

Hence, Both the median and the range changed.

To know more about median and range click the link given below.

brainly.com/question/9045470

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faltersainse [42]

Answer:

  congruent by the SSS congruence postulate

Step-by-step explanation:

The hash marks tell you each side of one triangle has a congruent corresponding side in the other triangle.

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The triangles are congruent by the SSS congruence postulate.

7 0
2 years ago
Determine the Domain of: 8(x)=(4)/(x-9)
Charra [1.4K]

Hi !

f(x) =  \frac{4}{x - 9}

x-9 must be different from 0.

x -9 \ne0 \\ x \ne9

=  =  >  \: D_f=\mathbb{R}-\{9\}

Have a nice day ;)

4 0
2 years ago
The Johnson family want to start a college fund for their daughter Gabriella. They put $63, 000 in to an account that grows at a
marissa [1.9K]

Answer:

  • 34.13 years

Step-by-step explanation:

<u>Given formula:</u>

  • G(t)= 63000(1 + 0.0255/4)^4t

<u>Need to find the value of t when G(t) = 150000</u>

  • 150000 = 63000( 1+ 0.0255/4)^4t
  • ( 1+ 0.0255/4)^4t = 150000/63000
  • ( 1+ 0.0255/4)^4t = 2.3809
  • 4t* log( 1+ 0.0255/4) = log 2.3809
  • 4t *0.00275983965 = 0.37674115501
  • t = 0.37674115501/(4*0.00275983965)
  • t = 34.13 years rounded

6 0
3 years ago
Need help on this too​
andrezito [222]

Answer:

I think it is distributive

Step-by-step explanation:

When a single number is next to parentheses, it's called distributive property

I hope this is right :/

Please mark brainliest :/

6 0
3 years ago
The ratio of the number of men to the number of women in a sports club is 5:2.
user100 [1]

Let the number of men and the number of women in the beginning be x and y

Now,\sf  \frac{x} {y} =\frac{5}{2} \\\\\sf=2x=5y \\\\\sf=x=\frac{5y}{2}

Now, In 2nd case,

No. Of men=x-63 and no. Of women =y-12

Now,the ratio becomes\frac{x-63}{y-12}=\frac{7}{4} \\\\\sf=4(x-63)=7(y-12) \\\\\sf=4x-252=7y-84 \\\\\sfPutting,\:x=\frac{5y}{2}\:in\: 4x-252=7y-84\:we\: get, \\\\\sf10y-252=7y-84 \\\\\sf=10y-7y=252-84 \\\\\sf=3y=168 \\\\\sf=y=56 \\\\\sf=\boxed{Y=56}

Now,we have, 2x=5y

Putting the value of Y=56 in 2x=5y,we get,

\sf 2x=5\:x\:56 \\\\\sfx=\frac{5\:x\:56}{2} \\\\\sfx=\frac{5\:x\: \cancel{56}\:\:28}{ \cancel{2}} \\\\\sf=x=5\: x\: 28 \\\\\sfx=140 \\\\\sf\boxed{x=140}

Hence, the number of men was 140 and the no. of women was 56

Hi...I am from India.. Where are you from?

8 0
3 years ago
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