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olganol [36]
3 years ago
9

A car travels at a constant speed of 40 mph on the highway.

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer:no

Step-by-step explanation:the trafic may slow down or stop

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Which two expressions have the same value?
Wewaii [24]

Answer:

One and two

Step-by-step explanation:

The answer is one and two since you would first multipy anyway using pemdas

7 0
2 years ago
Read 2 more answers
Find a point slope form for the line with slope 1/5 and passing through the point (-3,-9)
alisha [4.7K]

Answer:

y+9=1/5(x+3)

Step-by-step explanation:

Point slope formula: y-y1=m(x-x1)

slope=m

m=1/5

-3=x1 -9=y1

y-(-9) =1/5(x-(-3))

simplify...

y+9=1/5(x+3)

hope this helps!! :)

5 0
3 years ago
NEED HELP THIS IS SOOOOOO HARD NEED PROOF <br> WILL GIVE BRAINLIEST AND 5-STAR
Shkiper50 [21]

Answer:

J    1

   --------

    x^2 -x

Step-by-step explanation:

x+1

----------

x^3-x

Factor out an x in the denominator

x+1

----------

x(x^2-1)

We can factor the terms in the parentheses because it is a difference of squares

x+1

----------

x(x-1) (x+1)

Canceling the x+1 terms

1

----------

x(x-1)

Distribute in the denominator

1

--------

x^2 -x

7 0
3 years ago
In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.
artcher [175]

Answer:

21.9°

Step-by-step explanation:

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.

We solve this above question using the Sine rule

a/sin A = b/sin B

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet.

Hence:

HI/∠J = JH/∠H

= 8/sin 90° = 1.9/sin ∠H

Cross Multiply

∠H = arc sin(sin 1.9 × 90/8)

∠H = 21.9°

5 0
2 years ago
Suppose the number of gallons of gasoline per day used by a car is normally distributed with a mean of 2.2 gallons and a standar
const2013 [10]
The difference in gallons per day used is 3.6.

The formula to calculate a z-score is:
z=\frac{X-\mu}{\sigma},

where X is the value used to calculate the score, μ is the mean and σ is the standard deviation.  We have the z-scores so we must work backward:

3=\frac{X-2.2}{1.2}\text{ and }0=\frac{X-2.2}{1.2}

For both equations, we will cancel the 1.2 by multiplying both sides:
3\times1.2=(\frac{X-2.2}{1.2})\times1.2\text{ and }0\times1.2=(\frac{X-2.2}{1.2})\times1.2&#10;\\&#10;\\3.6=X-2.2\text{ and }0=X-2.2

Now we will cancel 2.2 from both equations by adding it to both sides:

3.6+2.2=X-2.2+2.2     and       0+2.2=X-2.2+2.2
5.8=X     and       2.2=X

The difference in gas used per day would be given by
5.8-2.2 = 3.6.
5 0
3 years ago
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