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Paha777 [63]
3 years ago
12

I need help if you can that would be great thank you

Mathematics
1 answer:
liq [111]3 years ago
5 0

Answer:

Simplifying the expression (3\:.\:2)^5\div (3^2\:.\:2^3) so, there is only one power of each base we get \mathbf{3^3\:.\:2^2}

Option D is correct answer.

Step-by-step explanation:

We need to simply the expression (3\:.\:2)^5\div (3^2\:.\:2^3) so, there is only one power of each base.

Solving:

(3\:.\:2)^5\div (3^2\:.\:2^3)

We can write it as:

\frac{(3\:.\:2)^5}{3^2.2^3}

Now using exponent rule: (a\:.\:b)^m=a^m\:.\:b^n

\frac{3^5\:.\:2^5}{3^2.2^3}

Now using the exponent rule: \frac{a^m}{a^n}=a^{m-n} the bases should be same

3^{5-2}\:.\:2^{5-3}\\=3^3\:.\:2^2

So, simplifying the expression (3\:.\:2)^5\div (3^2\:.\:2^3) so, there is only one power of each base we get \mathbf{3^3\:.\:2^2}

Option D is correct answer.

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Wendy winholtz 8 year savings certificate pays an annual interest rate of 5.3% at the end of 5 years she cashed out the 6,000 CD
Vlad [161]

Answer:

  318

Step-by-step explanation:

The rate of 5.3% is an annual rate, and specifies the amount of interest earned in a 12-month period by the principal amount of the CD. The interest amount is found by multiplying the interest rate by the principal amount.

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<h3>penalty</h3>

The amount of the penalty is 5.3% of 6000:

  0.053 × 6000 = 318

Wendy paid a penalty of 318 for her early withdrawal.

8 0
2 years ago
How do I plot these in order because I’ve tried it multiple times and I cannot get the right answer.
Anika [276]

Answer:

This shape is somewhat like a square, I believe.

Step-by-step explanation:

1st Point: Inside the I quadrant (the top right), by moving 1 1/2 units to the right on the x-axis, and 4 units up.

2nd Point: Inside the IV quadrant (bottom right), by moving 1 1/2 units to the right on the x-axis, and 8 units down.

3rd Point: Inside the IV quadrant (bottom right), by moving 5 units to the right on the x-axis, and 8 units down.

4th Point: Inside the I quadrant, by moving 5 units to the right on the x-axis, and 4 units up.

8 0
3 years ago
Lf a boat with a value of $27,000 depreciates at a rate of 19% per year,
ruslelena [56]
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i hope this helpsss
4 0
3 years ago
Can someone help me with this: Eighty, decreased by three times an number, is the same as five times the number, increased by ei
enot [183]

Eighty, decreased by three times an number, is the same as five times the number, increased by eight. Then the number is 9

<h3><u>Solution:</u></h3>

Given that eighty, decreased by three times an number, is the same as five times the number, increased by eight

<em><u>To find: the number</u></em>

Let the required number be "a"

Let us break the given sentence

<em>Eighty decreased by three times an number = five times the number increased by eight</em>

Here "times" represents multiplication and "decreased" represents subtraction and "increased represents "addition"

80 - three times "a" = 5 times "a" + 8

80 - 3a = 5a + 8

80 - 8 = 5a + 3a

8a = 72

<h3>a = 9</h3>

Thus the required number is 9

6 0
3 years ago
An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

t= \frac{-80\pm \sqrt{6400+19200}}{-32}

t= \frac{-80\pm \sqrt{25600}}{-32}  

Simplify:

t = -\frac{5}{2} = -2.5 sec and t = \frac{15}{2} = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0
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