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Paha777 [63]
3 years ago
12

I need help if you can that would be great thank you

Mathematics
1 answer:
liq [111]3 years ago
5 0

Answer:

Simplifying the expression (3\:.\:2)^5\div (3^2\:.\:2^3) so, there is only one power of each base we get \mathbf{3^3\:.\:2^2}

Option D is correct answer.

Step-by-step explanation:

We need to simply the expression (3\:.\:2)^5\div (3^2\:.\:2^3) so, there is only one power of each base.

Solving:

(3\:.\:2)^5\div (3^2\:.\:2^3)

We can write it as:

\frac{(3\:.\:2)^5}{3^2.2^3}

Now using exponent rule: (a\:.\:b)^m=a^m\:.\:b^n

\frac{3^5\:.\:2^5}{3^2.2^3}

Now using the exponent rule: \frac{a^m}{a^n}=a^{m-n} the bases should be same

3^{5-2}\:.\:2^{5-3}\\=3^3\:.\:2^2

So, simplifying the expression (3\:.\:2)^5\div (3^2\:.\:2^3) so, there is only one power of each base we get \mathbf{3^3\:.\:2^2}

Option D is correct answer.

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