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Vsevolod [243]
3 years ago
5

Solve by factorisation 2x^2+3x-20

Mathematics
2 answers:
olga2289 [7]3 years ago
7 0

Answer:

(x + 4) × (2x - 5)

Step-by-step explanation:

  • Begin by writing 3x as a difference
  • 2x^2 + 8x - 5x - 20

  • Factor out 2x from the expression
  • 2x × (x + 4) - 5x - 20

  • Factor out -5 from the expression
  • 2x × (x + 4) - 5 (x + 4)

  • Factor out x + 4 from the expression
  • (x + 4) × (2x - 5)

Hope this helps!!

Lynna [10]3 years ago
7 0

Answer:

Answer:

(2x−5)(x+4)

Step-by-step explanation:

Factor 2x2+3x−20

2x2+3x−20

=(2x−5)(x+4)

Answer:

(2x−5)(x+4)

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