Answer:
<em>Answer is </em><em>given below with explanations</em><em>. </em>
Step-by-step explanation:
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If the mean time between unscheduled maintenance of LCD displays in a hospital’s CT scan facility is 4000 hours, what is the pro
1 answer:
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1. Method 1: By Listing MultiplesList out all multiples of each denominator, and find the first common one.
2: 2 , 4
4: 4
Therefore, the LCD is 4
Method 2: By Prime FactorsList all prime factors of each denominator, and find the union of these primes.
Therefore, the LCD is <span>2 x 2 = 4
</span>
2. <span>Make the denominators the same as the LCD
</span>
<span>
3. </span><span>Simplify. Denominators are now the same.
</span>
4. Join the denominators
5. <span>Simplify
</span>
<span>
Done! :) </span><span>Decimal Form: -0.25</span>
2: 2 , 4
4: 4
Therefore, the LCD is 4
Method 2: By Prime FactorsList all prime factors of each denominator, and find the union of these primes.
Therefore, the LCD is <span>2 x 2 = 4
</span>
2. <span>Make the denominators the same as the LCD
</span>
<span>
3. </span><span>Simplify. Denominators are now the same.
</span>
4. Join the denominators
5. <span>Simplify
</span>
<span>
Done! :) </span><span>Decimal Form: -0.25</span>
Answer:
The fraction of the students who failed to went partying =
Step-by-step explanation:
Let total number of students = 100
No. of students partied are twice the no. of students who not partied.
⇒ No. of students partied = 2 × the no. of students who are not partied
No. of students partied before the exam = 20 % of total students
⇒ No. of students partied before the exam = × 100
⇒ No. of students partied before the exam = 20
No. of students who not partied before the exam =
Thus the fraction of the students who failed to went partying =