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Snezhnost [94]
3 years ago
5

If the mean time between unscheduled maintenance of LCD displays in a hospital’s CT scan facility is 4000 hours, what is the pro

bability of unscheduled maintenance in the next 6000 hours
Mathematics
1 answer:
musickatia [10]3 years ago
6 0
Likely

6000 hours is over the mean average, but it is not impossible that it will not happen.
You might be interested in
Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ < 360°.
inna [77]

Answer:

First part

The answer is (5 square root 2, 45°), (-5 square root 2, 225°) ⇒ answer (d)

Second part

The equation in standard form for the hyperbola is y²/81 - x²/19 = 1 ⇒ answer(b)

Step-by-step explanation:

First part:

* Lets study the Polar form and the Cartesian form

- The important difference between Cartesian coordinates and

  polar coordinates:

# In Cartesian coordinates there is exactly one set of coordinates

  for any given point.

# In polar coordinates there is an infinite number of coordinates

   for a given point. For instance, the following four points are all

   coordinates for the same point.

# In the polar the coordinates the origin is called the pole, and

  the x axis is called the polar axis.

# The angle measurement θ can be expressed in radians

   or degrees.

- To convert from Cartesian Coordinates (x , y) to

  Polar Coordinates (r , θ)

# r = ± √(x² + y²)

# θ = tan^-1 (y / x)

* Lets solve the problem

- The point in the Cartesian coordinates is (5 , 5)

∵ x = 5 and y = 5

∴ r = ± √(5² + 5²) = ± √50 = ± 5√2

∴ tanФ = (5/5) = 1

∵ tanФ is positive

∴ Angle Ф could be in the first or third quadrant

∵ Ф = tan^-1 (1) = 45°

∴ Ф in the first quadrant is 45°

∴ Ф in the third quadrant is 180 + 45 = 225°

* The answer is (5√2 , 45°) , (-5√2 , 225°)

Second part:

* Lets study the standard form of the hyperbola equation

- The standard form of the equation of a hyperbola with  

  center (0 , 0) and transverse axis parallel to the y-axis is

  y²/a² - x²/b² = 1, where

• the length of the transverse axis is 2a

• the coordinates of the vertices are (0 , ±a)

• the length of the conjugate axis is 2b

• the coordinates of the co-vertices are (±b , 0)

•      the coordinates of the foci are (0 , ± c),  

• the distance between the foci is 2c, where c² = a² + b²

* Lets solve our problem

∵ The vertices are (0 , 9) and (0 , -9)

∴ a = ± 9 ⇒ a² = 81

∵ The foci at (0 , 10) , (0 , -10)

∴ c = ± 10

∵ c² = a² + b²

∴ (10)² = (9)² + b² ⇒ 100 = 81 + b² ⇒ subtract 81 from both sides

∴ b² = 19

∵ The equation is  y²/a² - x²/b² = 1

∴  y²/81 - x²/19 = 1

* The equation in standard form for the hyperbola is y²/81 - x²/19 = 1

3 0
3 years ago
Given the following equation of the hyperbola, what are the x-values of the vertices? x^2/4 - y^2/49 = 1 is it 2 and -2?
Jet001 [13]

Answer:

  yes, ±2

Step-by-step explanation:

The x-intercepts are found by setting y=0 and solving for x:

  x^2/4 = 1

  x^2 = 4

  x = ±√4

  x = ±2

The x-values of interest are -2 and +2.

3 0
3 years ago
in a school gym, the ratio of the number of boys to the number of girls was 4:3 . after 160 boys left the gym, the ratio became
Annette [7]

Answer:

300 girls were there in the gym.

Step-by-step explanation:

Given:

The ratio of the number of boys to the number of girls was 4:3, after 160 boys left the gym, the ratio became 4:5.

Now, to find the number of girls in the gym.

The girls in the gym does not left, their quantity is same before and after.

So, we multiply the both ratios to make the girls ratio same:

4:3 × 5 = 20:15

4:5 × 3 = 12:15

Now, <em>we find the units of the ratio</em>.

<em>The ratio of boys dropped down by 160</em>:

20 - 12 = 8 units.

160 = 8 units

Now, dividing both sides by 8 we get:

20 = 1 unit

So, 1 unit = 20.

Now, girls = 15 units

So, 15 × 20 = 300.

Therefore, 300 girls were there in the gym.

3 0
4 years ago
For what values of K does x2+kx+9=0
Airida [17]

Answer:

k = 6

Step-by-step explanation:

x {}^{2}  + kx + 9 = 0

here,

a = 1,

b = k

c = 9

now,

D = b {}^{2}  - 4ac

k {}^{2}  - 4(1)(9) = 0 \\   k {}^{2}  - 36 = 0 \\ k {}^{2}  = 36 \\ k = 6

4 0
3 years ago
Create a pattern with the rule. -4.
Bumek [7]
One pattern is 22, 18, 14, 10, 6, 2 hope this helps just keep subtracting 4. You can go from the highest number to the lowest. Thanks for asking!
7 0
3 years ago
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