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jenyasd209 [6]
2 years ago
13

Anyone know how to do it

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
4 0

Answer:

Surface area of cube = 6x²

surface area of cube = surface area of sphere

it means that 6x²=4πr²

x²=

\frac{4\pi {r}^{2}  }{6}  =  \frac{4 \pi9}{6}  =  \frac{4\pi3}{2}  = 6\pi

x =   \sqrt{6\pi}

\sqrt{6\pi}  =  \sqrt{k\pi}

6\pi = \pi \: k

k = 6

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Select all the conditions for which it is possible to construct a triangle. (7.G.1.2) Group of answer choices a. A triangle with
saw5 [17]

Answer:

  b, d, e, f

Step-by-step explanation:

Here are the applicable restrictions:

  • The sum of angles in a triangle is 180°, no more, no less.
  • The sum of the lengths of the two shortest sides exceeds the longest side.
  • When two sides and the angle opposite the shortest is given, the sine of the given angle must be at most the ratio of the shortest to longest sides.

a. A triangle with angle measures 60°, 80°, and 80° (angle sum ≠ 180°, not OK)

b. A triangle with side lengths 4 cm, 5 cm, and 6 cm (4+5 > 6, OK)

c. A triangle with side lengths 4 cm, 5 cm, and 15 cm (4+5 < 15, not OK)

d. A triangle with side lengths 4 cm, 5 cm, and a 50° angle across from the 4 cm side (sin(50°) ≈ 0.766 < 4/5, OK)

e. A triangle with angle measures 30° and 60°, and an included 3 cm side length (OK)

f. A triangle with angle measures 60°, 20°, and 100° (angle sum = 180°, OK)

_____

<em>Additional comment</em>

In choice "e", two angles and the side between them are specified. As long as the sum of the two angles is less than 180°, a triangle can be formed. The length of the side is immaterial with respect to whether a triangle can be made.

__

The congruence postulates for triangles are ...

  SSS, SAS, ASA, AAS, and HL

These essentially tell you the side and angle specifications necessary to define <em>a singular triangle</em>. As we discussed above, the triangle inequality puts limits on the side lengths specified in SSS. The angle sum theorem puts limits on the angles when only two are specified (ASA, AAS).

In terms of sides and angles, the HL postulate is equivalent to an SSA theorem, where the angle is 90°. In that case, the angle is opposite the longest side (H). In general, SSA will specify a singular triangle when the angle is opposite the <em>longest</em> specified side, regardless of that angle's measure. However, when the angle is opposite the <em>shortest</em> specified side, the above-described ratio restriction holds. If the sine of the angle is <em>less than</em> the ratio of sides, then <em>two possible triangles are specified</em>.

4 0
2 years ago
Which expression is equivalent to (4x^(3)y^(5))(3x^(5)y)^(2)
marshall27 [118]

Answer:

(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7

Step-by-step explanation:

Given

(4x^3y^5)(3x^5y)^2

Required

The equivalent expression

We have:

(4x^3y^5)(3x^5y)^2

Expand

(4x^3y^5)(3x^5y)^2 = 4x^3y^5*9x^{10}y^2

Further expand

(4x^3y^5)(3x^5y)^2 = 4*9*x^3*x^{10}y^5*y^2

Apply laws of indices

(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7

8 0
3 years ago
Find angle v and solve for x
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3 years ago
Find the mean, median, and mode of 14, 15, 3, 15, 14, 14, 18, 15, 8, 16.
klemol [59]

Answer:

mean: 13.2 (average)

median: 14.5 (Center)

mode: 14 and 15 (because data is bimodal so there are two modes

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
A dressmaker needs to cut 18-inch pieces of ribbon from rolls of ribbon that are 6 feet
SashulF [63]
You have 10 rolls and each is 6 feet so therefore you have 60 feet of ribbon. Convert that to inches you need to multiply by 12 so 60 x 12 = 720 inches of ribbon.
If the dress maker needs 18 inch pieces you divide to 720 by 18.
720 divided by 18 will give you 40 pieces.

Final answer:

The dressmaker will get 40, 18-inch pieces of ribbon from 10, 6 foot rolls.
4 0
3 years ago
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