Answer:
8. adjacent 9. vertical 10. adjacent
Step-by-step explanation:
Answer:
The solutions are given below:
Step-by-step explanation:
x(x-3)+4(x²+2)
= x²-3x+4x²+8
= x²+4x²+8-3x
= 5x²+8-3x
2(a+5)-3(a+7)
= 2a+10-3a-21
= 2a-3a+10-21
= -a-11
xy(x²yz-xy²z+xyz²)
= x³y²z-x²y³z+x²y²z²
-4(a²-2a+8)
= -4a²+8a-32
<h3>
Hope it helps !</h3>
Answer:
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation:
Answer:
-1
Step-by-step explanation:
2x² - 5x + 7 is subtracted <em>from </em>x² + 2x - 11, so
(x² + 2x - 11) - (2x² - 5x + 7)
x² + 2x - 11 - 2x² + 5x -7 (Distribute the negative)
-x² + 7x - 18 (Combine like terms)
The leading coefficient is the coefficient of the first term, so it is -1.
