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almond37 [142]
3 years ago
15

In triangle ABC, the bisectors of angle A, angle B, and angle C cut the opposite sides into lengths a1, and

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
8 0

Question

In triangle ABC, the bisectors of angle A, angle B, and angle C cut the opposite sides into lengths a1, and

a2, b1, and b2, and c1 and c2, respectively, labeled in order counterclockwise around triangle ABC for

a1 = 5/3, a2 = 10/3,b1 = 15/4. Find the perimeter of triangle ABC.

Step-by-step explanation:

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Which one is right triangle angle <br>a. 45, 55 and 35<br>b. 52, 48 and 20​
Gemiola [76]
<h2>option b. 52, 48 and 20</h2>

Step-by-step explanation:

<u>let's solve:-</u>

  • To test whether given this triangle is right triangle or not, we can use the Pythagorean Theorem .

soo

Pythagorean Theorem=

\bold \green{(leg1)^{2} +(leg2)^{2} =(hypotenuse)^{2} }

<h2>_____________________________________</h2>

Here:-

\bold \blue{leg \: 1 = 48} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\ \bold  \blue{ leg2 = 20} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \bold\blue{hypotenuse = 52}

Putting values:-

{48}^{2}  +  {20}^{2}  = {52}^{2}   \:  \:  \:  \:  \:  \: \\  \\ 2304 + 400 = 2704 \\  \\ 2704 = 2704 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

<h2>_____________________________________</h2>
4 0
2 years ago
What is .50 as a benchmark fraction
Alinara [238K]

Answer: 1/2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Can someone please help me with this question?
MakcuM [25]
D is the answer. Hope this helped.
7 0
3 years ago
Read 2 more answers
Please help me on this
laiz [17]

Answer:

34

Step-by-step explanation:

Angles 3 and 7 are corresponding angles. When the lines defining the base of the corresponding angles are parallel (as in this case where a is parallel to b), then the angles are equal.

That's the heavy duty definition. It just means that corresponding angles in parallel lines are equal.

So if <3 = 34 degrees, then <7 = 34 degrees.

7 0
3 years ago
1. 4x-8+2x+-5x+x²-3=<br> 2.3x+5x=<br> 3.2r+4+3x-2=<br> 4.3x-2y-x+5y=<br> 5.2y²-8y³+5y-5y²+4y³=
Marrrta [24]
1. 4x - 8 + 2x + (-5x) + x^2 - 3 = 4x - 8 + 2x - 5x + x^2 - 3...now, we just combine like terms....lets group them...it will be easier ...x^2 + (4x + 2x - 5x ) - 8 - 3 = x^2 + x - 11

2. 2x + 5x = 8x

3. 2r + 4 + 3x - 2 = 3x + 2r + (4 - 2) = 3x + 2r + 2

4. 3x - 2y - x + 5y = (3x - x) + (5y - 2y) = 2x + 3y

5. 2y^2 - 8y^3 + 5y - 5y^2 + 4y^3 = (4y^3 - 8y^3) + (2y^2 - 5y^2) + 5y =
    -4y^3 - 3y^2 + 5y
3 0
3 years ago
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