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2 years ago

What is the value of the expression

Mathematics

2 answers:

prisoha [69]2 years ago

8 0

Answer:

Step-by-step explanation:

Follow the PEMDAS rule.

Parentheses

Exponent

Multiplication

Division

Addition

Subtraction

By following that rule, you know that you have to take care of the exponent first. 1/2 to the fourth power is 1/16. Then the next step in pemdas is to multiply that with 48, which is 3. The you subtract 3 from 9.

Hope this helps <3

Tomtit [17]2 years ago

5 0

Answer:

Step-by-step explanation:

mark brainliest please

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Bill and his friends went to red robin. Their order consisted of 2 hamburgers to $5.49 each, a chicken sandwich for $6.25, an or

Dvinal [7]

Answer:

47.27

Step-by-step explanation:

5.49+5.49+6.25+12.99+1.75+1.75+1.75+1.75=37.22

37.22×.20 for tip=7.44

37.22×.07 for tax=2.61

37.22+7.44+2.61=47.27

6 0

3 years ago

Read 2 more answers

Solve the equation: 9 (x − 9)−3 = −4 (2x + 4) 4 -4 100 68

Nina [5.8K]

Answer:

Step-by-step explanation:

Applying BODMAS here;

We first solve what is in the brackets:

9x - 81 -3 = -8x - 16

We then put the like terms together:

9x + 8x = -16 + 81 + 3

We then do the addition:

17x = -16 + 84

We then do the subtraction:

17x = 68

Simplifying this gives:

x = $\frac{68}{17}$ = 4

8 0

3 years ago

A circle is centered at the point (-7, -1) and passes through the point (8, 7).

Sergeu [11.5K]

we know the circle's center is at -7, -1, and we know the circle itself passes through 8,7, the distance from the center to a point on it is by definition its radius, therefore

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\\stackrel{center}{(\stackrel{x_1}{-7}~,~\stackrel{y_1}{-1})}\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{7})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\\stackrel{radius}{r}=\sqrt{[8-(-7)]^2+[7-(-1)]^2}\implies r=\sqrt{(8+7)^2+(7+1)^2}\\\\\\r=\sqrt{15^2+8^2}\implies r=\sqrt{225+64}\implies \boxed{r=17}$

and since we know that x = -15 for such a point, then

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2\qquad center~~(\stackrel{-7}{ h},\stackrel{-1}{ k})\qquad \qquad radius=\stackrel{17}{ r}\\\\\\\[x-(-7)]^2+[y-(-1)]^2=17^2\implies (x+7)^2+(y+1)^2=289\\\\\\\stackrel{\textit{since we know x = -15}}{(-15+7)^2+(y+1)^2=289}\implies (-8)^2+\stackrel{FOIL}{(y^2+2y+1^2)}=289\\\\\\64+y^2+2y+1=289\implies y^2+2y=224\implies y^2+2y-224=0\\\\\\(y+16)(y-14)=0\implies y=\begin{cases}-16\\14\end{cases}$