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Alecsey [184]
3 years ago
8

Suppose that triangle ABC is a right triangle with a right angle at C and hypotenuse C. Also note that a is the length of the si

de opposite angle A and b is the length of the side opposite angle B Given that b 13 and C - 15, determine the values indicated below. Round to four decimal places when needed a- degrees. degrees.

Mathematics
1 answer:
gavmur [86]3 years ago
6 0

Answer:

The value of a is 7.4833. The value of A=29.9262^0 and B=60.0735^0.

Step-by-step explanation:

Consider the provided information.

The required figure is shown below:

We need to find the value of a.

Calculate the value of a by using Pythagorean theorem.

a^2+b^2=c^2

a^2+(13)^2=(15)^2

a^2=225-169

a^2=56

a=7.4833

Hence, the value of a is 7.4833.

Now find the value of angle A as shown:

\sin A=\frac{a}{c}

\sin A=\frac{7.4833}{15}

A=sin^{-1}(0.4989)

A=29.9262^0

Find the value of angle B as shown:

\sin B=\frac{b}{c}

\sin B=\frac{13}{15}

B=sin^{-1}(0.8667)

B=60.0735^0

Hence, the value of A=29.9262^0 and B=60.0735^0.

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4 0
3 years ago
Suppose that 15% of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in t
hram777 [196]

Answer:

a.\mu=15

b.\mu=7.8586 \ and  \ \mu=22.1414

c. Choice A- Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

Step-by-step explanation:

a.Binomial distribution is defined by the expression

P(X=k)=C_k^n.p^k.(1-p)^{n-k}

Let n be the number of trials,n=100

and p be the probability of success,p=15\%

The mean of a binomial distribution is the probability x sample size.

\mu=np=100\times0.15=15

b.Limits within which p is approximately 95%

sd of a binomial distribution is given as:\sigma=\sqrt npq\\q=1-p

Therefore, \sigma=\sqrt(100\times0.015\times0.85)=3.5707

Use the empirical rule to find the limits. From the rule, approximately 95% of the observations are within to standard deviations from mean.

sd_1=>\mu-2\sigma=15-2\times3.3507=7.8586\\sd_2=>\mu-2\sigma=15+2\times3.3507=22.1414

Hence, approximately 95% of the observations are within 7.8586 and 22.1414 (areas of infestation).

c.  x=45 is not within the limits in b above (7.8586,22.1414). X=45 appears to be a large area of infestation. A.Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

4 0
3 years ago
use the intermediate value theorem to determine, if possible, whether g(x)=2x^3+3x^2-3x+4 has a real zero between -2 and -1
inn [45]

Answer:

Step-by-step explanation:

g(-2)=2(-2)^3+3(-2)^2-3(-2)+4=-16+12+6+4=6

g(-1)=2(-1)^3+3(-1)^2-3(-1)+4=-2+3+3+4=8

it does  not change sign ,so there is no real zero between -2 and -1.

3 0
3 years ago
1J
Harlamova29_29 [7]

Answer:

(1,-1)

Step-by-step explanation:

We can solve the system by using substitution.

In order to do this we must make x the subject in the first equation.

We can do this by simply subtract 2y from both sides

x + 2y = -1

subtract 2y from both sides

x + 2y - 2y = -1 - 2y

simplify

x = -2y - 1

now that we have made x the subject in one of the equations we can plug in (or substitute) the value of x into the other equation

2x – 3y = 5

x = -2y - 1

2(-2y - 1) - 3y = 5

We can then solve for y

2(-2y - 1) - 3y = 5

Distribute the 2

-4y - 2 - 3y = 5

combine like terms -4y + -3y

-7y - 2 = 5

add 2 to both sides

-7y = 7

divide both sides by -7

y = -1

Now that we have found the value of y we can plug in the value of y into one of the equations and solve for x

x + 2y = -1

y = - 1

x + 2(-1) = -1

multiply 2 and -1

x + -2 = -1

add 2 to both sides

x = 1

So we have found that x = 1 and y = -1 therefore the solution to the system of equations is (1,-1)

7 0
3 years ago
Read 2 more answers
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LiRa [457]

Statement 1 is false.

While it is true that some of the y-values have more than one corresponding x-value, this does not make the relation not a function.  It would not be a function if some of the <em>x-values</em> had more than one corresponding y-values.

Statement 2 is true.

The domain of a function is all the x-values it encompasses.  This function starts at 3 and ends at 8.

Statement 3 is false.

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Hope this helps!!

5 0
3 years ago
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