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lilavasa [31]
2 years ago
6

Anyone have any idea of what this could be please help asap

Mathematics
2 answers:
fiasKO [112]2 years ago
8 0

Answer:

20

Step-by-step explanation:

divided 12 by three since it mirrors the shape on a smaller scale. you get 4. multiply that by five and there's your answer

Sidana [21]2 years ago
7 0

Answer:

u use similar figures to find it out

3/12=x/5

then u cross multiply

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What is the pobability that a number cube with six
Snowcat [4.5K]

Answer: \dfrac{1}{6}

Step-by-step explanation:

We know that the total number of outcomes for fair dice {1,2,3,4,5,6} = 6

Given : Favorable outcome = 5

i.e. Number of favorable outcomes =1

We know that the formula to find the probability for each event is given by :-

\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}

Then, the probability that the six  faces cube will land with the number 5 face up will be :_

\dfrac{1}{6}

Hence, the required probability = \dfrac{1}{6}

5 0
3 years ago
Select the correct answer choice below: *<br> Captionless Image
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Answer:

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Step-by-step explanation:

3 0
3 years ago
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What is -38/-5 as a decimal?
sesenic [268]
Divide -38 by -5
The negatives cancel out since a negative divided by a negative is a positive.
7.6
5 0
3 years ago
3. Two squares were used to form the following figure. What is the area of the shaded region?
Tasya [4]
C


the shades part 14 x14 = 196
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5 0
3 years ago
A marathon is 26.2 miles. What is the least number of times Miguel must run for his total distance run during training to exceed
ziro4ka [17]

Missing part of the question

Miguel has started training for a race. The first time he trains, he runs 0.5 mile. Each subsequent time he trains, he runs 0.2 mile farther than he did the previous time.

What is the arithmetic series that represents the total distance Miguel has run after he has trained n times?

Answer:

The least number of times Miguel must run for his total distance run during training to exceed the distance of a marathon is 17.3 miles

Step-by-step explanation:.

Given parameters

Miguel first run = 0.5 mile

Subsequent run = 0.2 mile

This question is an arithmetic progression.

We'll make use of arithmetic progression formula to solve this

Formula:.

Tn = a + (n - 1)d

Where a = first term

n = number of terms

d = common difference

In this case

a = first run = 0.5 mile

d = subsequent run = 0.2 mile

So, Tn = a + (n - 1)d become

Tn = 0.5 + (n - 1) 0.2

Tn = 0.5 + 0.2n - 0.2

Tn = 0.5 - 0.2 + 0.2n

Tn = 0.3 + 0.2n

The arithmetic series of an arithmetic progression is calculated using

Sn = ½(a + Tn) * n

By substituton, we have

Sn = ½(0.5 + 0.3 + 0.2n) * n

Sn = ½(0.8 + 0.2n) * n

Sn = 0.4n + 0.1n²

b.

Since the race is 26.2 miles then the least number of times is given as

Sn ≥ 26

0.4n + 0.1n² ≥ 26.2

0.1n² + 0.4n - 26.2 ≥ 0

Using quadratic formula

n = (-b ± √(b² - 4ac))/2a

Where b = 0.4 a = 0.1 and C = -26.2

So,

n = -0.4 ± √(0.4² - 4 * 0.1 * ,26.2)/2 * 0.1

n = (-0.4 ± √10.64)/0.2

n = (0.4 ± 3.26)/0.2

n = (0.4 + 3.26)/0.2 or (0.4 - 3.26)/0.2

n = 3.46/0.2 or -2.86/0.2

n = 17.3 or -14.3

Since n can't be negative

n = 17.3 miles

The least number of times Miguel must run for his total distance run during training to exceed the distance of a marathon is 17.3 miles

7 0
3 years ago
Read 2 more answers
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