Answer:
I would suggest he decrease the sales price.
Explanation:
Because it will might make people rush the product due to its low price compared to other products of another brand.
The low price will create a high demand for the product therefore causing the quantity of the products being produced to increase.
The quality of the product will be very good since the quality is not being reduced only the price therefore it might result in not having the maximum profit needed.
Answer: A clear statement of the problem
Explanation:
The opening of a direct claim message should clearly state the problem that you would like to be addressed by the receiver and would set the tone for the rest of the message.
Claim messages are formal messages and as such, should be clear and concise so that the message is communicated effectively and there is a lesser chance of the message being misread. This is why the message should be clearly stated, so that the receiver understands it and responds in kind.
Answer:
The one entry is recorded
Explanation:
The journal entry is shown below:
Inventory A/c Dr (Ending inventory) $10,000
Cost of goods sold A/c Dr (Balancing figure) $94,000
To Inventory A/c Dr (Beginning inventory) $5,000
To Purchase account $99,000
In mathematically,
Cost of goods sold = Beginning inventory + purchase - ending inventory
= $5,000 + $99,000 - $10,000
= $94,000
Answer:
$10.19 per share
Explanation:
With regards to the above, the basic earnings per common share is seen below;
Preferred dividend = Shares × Par value × Shares percentage
= 5,800 × $100 × 5%
= $29,000
So, basic earning per share = (Net income - Preferred dividend) ÷ Common shares
= ($620,000 - $29,000) ÷ 58,000
= $10.19 per share
Therefore, for 2021, basic earnings per common share amounted to $10.19
Answer:
a) H0: u = presence of a unit root
HA: u ≠ presence of a unit root ( i.e. stationary series )
b) t stat = -0.064
c) We will reject the Null hypothesis and the next step will be to accept the alternative hypothesis
d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise
Explanation:
<u>a) stating the null and alternative hypothesis</u>
H0: u = presence of a unit root
HA: u ≠ presence of a unit root ( i.e. stationary series )
<u>b) performing the test </u>
critical value = -2.88
T stat = coefficient / std error
= -0.02 / 0.31 = -0.064
c) From the test, the value of T stat > critical value we will reject the Null hypothesis hence the next step will be to accept the alternative hypothesis
d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise
