1) The graph consists of three horizontal segments, with discontinuities (jumps) at x = 1, x = 2, and x = 3.
A horizontal segment at y = - 2 for the values x = 0 to 1.
A horizontal segment at y = - 1 for values x = 1 to 2
A horizontal segment at y = 0 for values x - 2 to 3.
2) To know whether the end points of a segment are defined by the left or the right values you have to look for the circle at the extreme of the segment: if it is a solid dot, means that the end is included, if is is an open circle (white inside) then the end is not included in that segment.
3) That function is based on the function named integer part because if relates y with the integer part of x.
The integer value function is [x] and it makes correspond y values witht he integer values of x.:
y = 0 witht the integer value of x for x between 0 and 1, excluding 1.
y = 1 with the integer value of x between 1 and 2 (excluding 2)
y = 2 with the integer value of x between 2 and 3 (excluding 3)
y = 3 with the integer value of x between 3 and 4 (excluding 4)
But our function is two units below, so it is [x] - 2
Answer:
Simple
Rise/Run
for one week they run 10 miles
2 weeks 20 miles
3 weeks 30 miles
4 weeks 40 miles
the rate of change would be 10/1 (Why? Because you rise +10 each time per week.)
divide that it would be 10 (:
gOoD lUCk
second answer copied me so.
Answer:
3, 5, 7
Step-by-step explanation:
1st number: (2k+1)
2nd number: (2k+3)
3rd number: (2k+5), k∈Z
3*[(2k+1) + (2k+3)] = 3 + 3*(2k+5)
3*(4k+4)=3+6k+15
12k+12=18+6k
6k=6
k=1
1st number: (2k+1) = 3
2nd number: (2k+3)=5
3rd number: (2k+5)=7
The two numbers are 12 and 15
<em><u>Solution:</u></em>
Let the smaller number be "x"
Let the larger number be "y"
Given that,
<em><u>The sum of two numbers is 27</u></em>
Therefore, we frame a equation as:
Smaller number + Larger number = 27
x + y = 27 ------ eqn 1
<em><u>The larger number is 3 more than the smaller number</u></em>
Larger number = 3 + smaller number
y = 3 + x ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
x + 3 + x = 27
2x + 3 = 27
2x = 27 - 3
2x = 24
<h3>x = 12</h3>
<em><u>Substitute x = 12 in eqn 2</u></em>
y = 3 + 12
<h3>y = 15</h3>
Thus the two numbers are 12 and 15
The fundamental principle of counting
