Answer:
From (-3,0) to (3,2) the equation is y=1/3x + 1 and the other side from (3,1) to (4,-1) is y= -3x + 11
Step-by-step explanation:
Thanks for helping me with the other one
Answer:
<em>First.</em> Let us prove that the sum of three consecutive integers is divisible by 3.
Three consecutive integers can be written as k, k+1, k+2. Then, if we denote their sum as n:
n = k+(k+1)+(k+2) = 3k+3 = 3(k+1).
So, n can be written as 3 times another integer, thus n is divisible by 3.
<em>Second. </em>Let us prove that any number divisible by 3 can be written as the sum of three consecutive integers.
Assume that n is divisible by 3. The above proof suggest that we write it as
n=3(k+1)=3k+3=k + k + k +1+2 = k + (k+1) + (k+2).
As k, k+1, k+2 are three consecutive integers, we have completed our goal.
Step-by-step explanation:
Answer:
A: y=1/3x+5
B: y=-2x+9
C: y=-3
D:y=2x+9
E: y=-10x+80
F:y=x-2
#1 rodney's error for
y=30x+10 is that he started off at 30 but he had to start off at 10 so it starts at (0,10) (1,40) (2,70) and keep going on by adding one to the x value and 30 to the y value
#2 rodneys error for
y=-1/2x+5 is that he went up by 1/2 instead of going down. it's a negative 1/2 so he had to go down
#3 Rodneys error for
y=x-2 is that he didn't start at (0.-2)
I'm not sure about the last picture but i think that it's
Tierra, Sharayah, Caleb, and Lang
Step-by-step explanation: