<h3>
Answer: A) Dashed line, shaded below</h3>
=============================================================
Explanation:
2x + 4y < 16 solves to y < -0.5x+4 when you isolate y. The inequality sign does not change direction because we divided both sides by a positive value (in this case, 4).
The graph of y < -0.5x+4 will be the same as the graph of 2x+4y < 16
To graph y < -0.5x+4, we graph y = -0.5x+4 which is a straight line that goes through the two points (0,4) and (2, 3). This is the boundary line of the inequality shaded region. The boundary line is a dashed line because we are not including points on the boundary that are part of the solution set. We only include these boundary points if the inequality sign has "or equal to".
We then shade below the dashed boundary line to indicate points below the boundary line. The shading is done downward due to the "less than" sign.
---------------------
Perhaps another method to find what direction we shade is we can try out a point like (0,0). The point cannot be on the boundary line.
Plug those coordinates into either equation. I'll pick the second equation
y < -0.5x+4
0 < -0.5*0+4
0 < 0+4
0 < 4
The last inequality is true, so the first inequality is also true when (x,y) = (0,0). Therefore, the point (0,0) is in the shaded region. The point (0,0) is below the boundary line y = -0.5x+4
So this is another way to see that the shaded region is below the boundary line.
Answer:
B
Step-by-step explanation:
Given 2 quantities that vary directly, then the graph must pass through the origin.
Nikiya's graph is the only one to do this ⇒ B
<span>2.1e-10
= 2.1 x 10^-10
= 0.00000000021
hope it helps</span>
Answer:
Just the second one is correct
Answer: D) 99 Points
Step-by-step explanation: Theresa earned scores of 88 points, 84 points, 88 points, and 91 points on four tests
Therefore the totals points are 351
351 is her total score for 4 tests, if she gets an average score of 90 on her fifth test then all we have to do is:
5 x 90 = 450 (The 5 being her fifth test)
450-351 = 99
Option D
