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Zarrin [17]
2 years ago
14

If x and y are complementary angles, then y is a right angle. right?

Mathematics
1 answer:
nevsk [136]2 years ago
3 0
Answer: No

Step-by-Step Explanation:

Complementary angles are a set of angles that sum up to 90 degrees. Neither y nor x can be 90 since if it is, then the other angle would have to be 0 degrees which is not possible in a triangle.
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A priori means as things were in the beginning or at the start.
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Evaluate each expression if a=2,6=-3,c=-1, and d=4.<br><br> 2d-a<br> ———-<br> b
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4 0
4 years ago
4. A geometric sequence is defined recursively by a(1) = 40 and a(n)= a(n-1)
Anarel [89]

The complete question is:

A geometric sequence is defined recursively by

    a_{(1)}=40\text{ and }a_n=(-1/2)a_{(n-1)}

(a) Write out the first four terms of this sequence.

(b) Is the 9th term of this sequence larger or smaller than 1/10? Show the calculation that you use to determine your answer.

Answer:

  • <u>The 9th term is larger than 1/10.</u>

Explanation:

You are given the first term,    a_(1)=40 , and the recursive formula

   a_{(n)}=(-1/2)a_{(n-1}

Thus, you can find the sequence of terms by multiplying each term by the constant ratio, (-1/2).

<u>(a) First four terms of the sequence</u>

a_{(1)}=40\\ \\ a_{(2)}=40\times (-1/2)=-20\\ \\ a_{(3)}=-20\times (-1/2)=10\\\\ a_{(4)}=10\times (-1/2)=-5

Those are the first four terms.

<u>(b) 9th term</u>

You can write the explicit formula of the sequence as:

a_{(n)}=a_{(1)}\times r^{(n-1)}\\ \\ a_{(n)}=40(-1/2)^{(n-1)}

Thus, for the 9th term, n = 9, and the term is:

a_{(9)}=40\times (-1/2)^{(9-1)}\\ \\ a_{(9)}=40\times(-1/2)^8\\ \\ a_{(9)}=40\times(1/256)=0.1526

Since 1/10 = 0.1, and 0.1 < 0.1526, the 9th term is larger than 1/10.

6 0
3 years ago
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