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3 years ago

What is the area of a square with a side length of 7 units

Mathematics

1 answer:

Alexandra [31]3 years ago

6 0

Answer:

343

Step-by-step explanation:

L×W×H= area

squares have equal L W And H

7×7×7= 343

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To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nicotine foun

QveST [7]

Answer:

We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 31.7 milligrams

Sample mean, $\bar{x}$ = 28.5 milligrams

Sample size, n = 9

Alpha, α = 0.05

Sample standard deviation, s = 2.8 milligrams

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 31.7\text{ milligrams}\\H_A: \mu < 31.7\text{ milligrams}$

We use One-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{28.5 - 31.7}{\frac{2.8}{\sqrt{9}} } = -3.429$

Now, $t_{critical} \text{ at 0.05 level of significance, 8 degree of freedom } = -1.860$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and accept the alternate hypothesis. We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.

3 0

3 years ago

Calculate x Give your answer correct to 1 d.p. Х 35° 15 cm<br> it is a trigonometry question.

OlgaM077 [116]

Here we are finding x, given the angle and adjacent side. To find x we will use the function cos as cos = a/h.

So let's do cos(35°) = 15cm / x

cos(35°) = 0.8 (1 dp)

x = 15 cm / cos(35°)

x = 18.3 cm (1 dp)

6 0

2 years ago

In the diagram above

Reil [10]

Answer:

Step-by-step explanation:

We have parallel lines.

Angles 1 and 2 are alternate angles.

With parallel lines, alternate angles are congruent.

Therefore

$m\angle1=m\angle2$

$m\angle1=2x+20,\ m\angle2=3x+10\\\\2x+20=3x+10\qquad\text{subtract 20 from both sides}\\\\2x+20-20=3x+10-20\\\\2x=3x-10\qquad\text{subtract}\ 3x\ \text{from both sides}\\\\2x-3x=3x-3x-10\\\\-x=-10\qquad\text{change the signs}\\\\x=10\\\\m\angle1=2(10)+20=20+20=40$