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Murljashka [212]
2 years ago
13

NO LINKS!!Please help me with these​

Mathematics
1 answer:
Julli [10]2 years ago
6 0

Answer:

\textsf{If }\: X \sim\textsf{N}(\mu,\sigma^2)\:\textsf{ then }\: \dfrac{X-\mu}{\sigma}=Z, \quad \textsf{where }\: Z \sim \textsf{N}(0,1)        

<u>Math</u>

\textsf{If }\: X \sim\textsf{N}(71,6.5^2)\:\textsf{ then }\: \dfrac{X-71}{6.5}=Z, \quad \textsf{where }\: Z \sim \textsf{N}(0,1)

<u>Science</u>

\textsf{If }\: X \sim\textsf{N}(62,8.0^2)\:\textsf{ then }\: \dfrac{X-62}{8.0}=Z, \quad \textsf{where }\: Z \sim \textsf{N}(0,1)

<u>z-score Information</u>

  • Positive z-score = data point is above average
  • Negative z-score = data point is below average
  • z-score close to zero = data point is close to average
  • If a data point's z-score is below -3 or above 3 (more than 3 standard deviations from the mean) it can be considered unusual.

<u>Question 3</u>

<u>Math</u>

X=75 \implies Z=\dfrac{75-71}{6.5}\right) \implies Z=0.6154

<u>Science</u>

X=71 \implies Z= \dfrac{71-62}{8.0} \implies Z=1.125

The student's math score is below average, whereas their science score is above average.  Therefore, the student did better on the science test.

<u>Question 4</u>

<u>Math</u>

X=91 \implies Z=\dfrac{91-71}{6.5} \implies Z=3.0769

<u>Science</u>

X=85 \implies Z=\dfrac{85-62}{8.0} \implies Z=2.875

The student's math and science scores are both above average, but the math score is further away from the mean.  Therefore, the student did better on the math test.

<u>Question 5</u>

<u>Math</u>

X=65 \implies Z=\dfrac{65-71}{6.5} \implies Z=-0.9231

Science

X=54 \implies Z=\dfrac{54-62}{8.0} \implies Z=-1

The student's math and science scores are both below average, but the science score is further away from the mean.  Therefore, the student did better on the math test.

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Kaitlyn's older brother borrowed money for school he took out a loan that charges 6% simple interest he will end up paying 720 a
Inessa [10]

Answer:

529.41

Step-by-step explanation:

From the above question, we are to find the Principal

The formula to find the Principal (Initial amount invested) is =

P = A / (1 + rt)

Where

A = Amount paid after t years. = 720

r = rate of interest = 6% = 0.06

t = time in years = 6

First, converting R percent to r a decimal

r = R/100 = 6%/100 = 0.06 per year.

Solving our equation:

P = 720 / ( 1 + (0.06 × 6)) = 529.41176470588

Approximately

P = 529.41

Therefore, Kaitlyn's brother borrowed 529.41 for school

8 0
3 years ago
Simplify. (3x^5z)^5<br> a. 243x25z5<br> b. 243x25z5<br> c. 81x25z5<br> d. 15x25z5
sattari [20]
(3x^5z)^5 = 3^5(x^5)^5z^5 = 243 x^{5 \times 5}  z^{5} =243 x^{25}  z^{5}
6 0
4 years ago
What is the volatile acid/alkalinity relationship in a digester if the alkalinity is 2400 mg/L and the volatile acids are 90 mg/
damaskus [11]

The volatile acid/alkalinity relationship in a digester is volatile acid/alkalinity = 3/80

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Ratio of volatile acid to alkalinity = 90 mg/L ÷ 2400 mg/L = 3/80

The volatile acid/alkalinity relationship in a digester is volatile acid/alkalinity = 3/80

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0
2 years ago
I really need help on this.
Sav [38]
I think for part 2 it is 5/6 and for part 1 it is 5/12×4/3=20/36=5/6 which is ur answer
7 0
4 years ago
40 pages read in 20 minutes. what is the unit rate?
Alenkinab [10]

Answer:

2 pages per minute.

Step-by-step explanation:

40 pages / 20 minutes

= 40 / 20 = 4 / 2 = 2

Therefore, you read 2 pages per minute.

8 0
3 years ago
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