The pair of points (3,8) and (x, 6) are on the graph of am inverse variation. What is the missing value?

1 answer:

7 0

1)
y varies inversely with x 
y=k/x , where k is any constant 
y=-16 when x=-64 

-16 = k/ (-64) 
-16 = k/-64 
k=(-16)(-64) = 1024 

2) 
y =k/x , where k is any constant 

y=8 when x=3 
8 = k/3 
k=24 

y=24/x 
when y=6 
6 = 24/x 
6x=24 
x=4 

Missing value is 4 

3) 
xy/4=-3 
xy=-12 
y=-12/x 
y=kx 
k=-12 

4)

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3 years ago

Can someone help me with number 8 please? Thank you.

Naddik [55]

Answer: $-4 \le x \le 5$
Note: to write the domain in interval notation, you'd write [-4,5]
if you need the domain in set-builder notation, then you'd write $\left\{x|x\in\mathbb{R}, \ -4\le x\le 5\right\}$

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Explanation:

The domain is the set of possible x input values. Look at the left most point (-4,-1). The x coordinate here is x = -4. This is the smallest x value allowed. The largest x value allowed is x = 5 for similar reasons, but on the other side of the graph.

So that's how I got $-4 \le x \le 5$ (x is between -4 and 5; inclusive of both endpoints)

Writing [-4,5] for interval notation tells us that we have an interval from -4 to 5 and we include both endpoints. The square brackets mean "include endpoint"

Writing $\left\{x|x\in\mathbb{R}, \ -4\le x\le 5\right\}$ is the set-builder notation way of expressing the domain. The $x\in\mathbb{R}$ portion means "x is a real number"

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3 years ago

The coordinates of the vertices of quadrilateral ABCD are A(−4, −1), B(−1, 2), C(5, 1), and D(1, −3).

serg [7]

Answer:

Sorry this is late, but it could help future people. Answers are in the picture.

Step-by-step explanation:

I took the quiz. :)