Answer:
b) π /16 (1-1/e^2)
Step-by-step explanation:
For this case we have the following limits:
And we have semicircles perpendicular cross sections.
The area of interest is the enclosed on the picture attached.
So we are assuming that the diameter for any cross section on the region of interest have a diameter of
And then we can find the volume of a semicircular cross section with the following formula:
And for th volum we can integrate respect to x and the limits for x are from 0 to 1, so then the volume would be given by this:
And evaluating the integral using the fundamental theorem of calculus we got:
And then the best option would be:
b) π /16 (1-1/e^2)
It is 11 because this app requires me to tip this long
Let's divide the shaded region into two areas:
area 1: x = 0 ---> x = 2
ares 2: x = 2 ---> x = 4
In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.
Area 1:
Area 2:
Therefore, the area of the shaded portion of the graph is
A = A1 + A2 = 5.34
You should distribute the 2. So you end up with 16w+8.
Step-by-step explanation:
Let ABCD be a rhombus. So, AC (AC = 14 cm) and BD (BD=48 cm) will be its diagonals. Let us assume that diagonals are intersecting at point O.
Since, diagonals of a rhombus are perpendicular bisector.
Hence, length of a side (or all) is 25 cm.