Answer:
the equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5)
= -5 = -2x + 15
Step-by-step explanation:
Write an equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5).
Using the slope intercept equation,
y = mx +c
m = slope = 1/2
For two lines to be perpendicular, the product of their slopes is -1
Let the slope of the other line be m2
m1×m2 =-1
1/2×m2 = -1
m2 = -1/(1/2) = -2
Slope of line = -2
For points (10, -5), x = 10, y =-5
-5 = -2× 10 +c
-5 = -20+ c
c = -5+20= 15
the equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5)
-5 = -2x + 15
Set this up as a proportion with the model stuff on top and actual building stuff on bottom.
. Cross multiply to get x = 780. The actual building is 780 inches. In feet that is 65.
Lightly draw a vertical line at -3 (x= -3 is the divider) on the left side graph x + 1, on the right side graph 1/2x + 2.
because these equations don't match up at the -3 coordinate, you have to draw an open (not colored in) circle at the beginning at the 1/2x-2 equation
If the equation of the circle is x^2+ y^2 = 41, we must first understand the parts of the equation.
A general circle's equation is (x-h)^2+(y-k)^2= r^2
(h.k) is the radius of the circle
r is the radius of the circle
Another useful fact to know is that tangent lines touch the circle at one point (4,5)
Since in our original equation there are no h or k values, we can assume that the center of the circle is (0,0).
The formula for slope is <u>Y1-Y2</u>
X1-X2
We can break this down with our two points (center and tangent)
(0,0) and (-4,-5)
(X1,Y1) and (X2,Y2)
therefore, we will put the equation as such
<u>0-(-5)= 5</u> = <em> </em><u><em>5</em></u>
0-(-4)= 4 <em> 4</em>
<em>this is our slope from the center to the point of tangency.</em>
We know that tangent lines are perpendicular to the radius, which we've already found the slope of. Perpendicular lines are opposite reciprocals of the line they are perpendicular to.
Therefore, we take our slope from center to the tangent, and make it opposite and then take the reciprocal of that slope, which will give us the slope of the tangent line itself. (note: reciprocal means flip the numerator and denominator)
<u>5</u> = <u>-5</u> = <u>-4</u><u>
</u>4 4 5
Now, we have a point on the line, and the line's slope. We can use slope-intercept equation to find the equation of the line.
Slope-int y=mx+b
(x,y) is a point,
m is the slope
b is the y intercept ( the point where x=0, or where its on the y axis)
now we plug things in
(-4,-5) is our point,
<u>-4</u> is our slope
5
-5=<u>-4</u>(-4)+b After we plug things in, solve for b
5
-5= 3.2+b
-1.8= b or b= <u />1 <u>4</u>
5
Now we just need to rewrite our equation with all our components.
(-4.-5) = point
<u>-4</u> = slope<u>
</u>5
1 <u>4</u> = y-intercept<u>
</u> 5
<em>y=</em><u><em>-4</em></u><em> x+ 1 </em><u><em>4</em></u><em> This is the equation of the tangent line</em><u>
</u><em> 5 5</em>
Hope that helped
You need to make a blank graph that goes from 1 to 10 in each direction and then just plot the points. sorry the picture is sideways idk how to fix it.
