The function f(x) = x2 has been translated 9 units up and 4 units to the right to form the function g(x). which represents g(x)?
1 answer:
A function assigns values of one set to another. The function that will represent g(x) is g(x)=(x-4)²+9.
<h3>What is a Function?</h3>A function assigns the value of each element of one set to the other specific element of another set.
As it is given to us that we need to move the graph of the function 9 units up and 4 units towards the right. Therefore, the function that will represent the new location of the graph can be written as,
Hence, the function that will represent g(x) is g(x)=(x-4)²+9.
Learn more about Function:
You might be interested in
Hello!
The Correct Answer to this would be 100%:
Option "85.4".
(Work Below)
Given:
height = 6m
chord = 20 m
We need to find the radius of the circle.
20 m = 2 √ [ 6m( 2 x radius - 6 m ) ]
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2
10 m = √ [ 6m( 2 x radius - 6 m ) ]
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ²
100 m² = 6 m( 2 x radius - 6 m )
100 m² = 12 m x radius - 36 sq m
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m²
136 m² = 12 m x radius
136 m² / 12 m = 12 m x radius / 12 m
<span>11.333 m = radius
</span>
the area beneath an arc:
Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h²<span> ).
</span>
r² = (11.333 m)² = 128.444 m²
r - h= 11.333 m - 6 m = 5.333 m
r * h = 11.333 m x 6 m = 68 m²
Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ]
Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ]
Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m
Area = 138.828 m² - 53.333 m²
Area = 85.4 m<span>²
</span>
Hope this Helps! Have A Wonderful Day! :)
And as Always...
The Correct Answer to this would be 100%:
Option "85.4".
(Work Below)
Given:
height = 6m
chord = 20 m
We need to find the radius of the circle.
20 m = 2 √ [ 6m( 2 x radius - 6 m ) ]
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2
10 m = √ [ 6m( 2 x radius - 6 m ) ]
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ²
100 m² = 6 m( 2 x radius - 6 m )
100 m² = 12 m x radius - 36 sq m
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m²
136 m² = 12 m x radius
136 m² / 12 m = 12 m x radius / 12 m
<span>11.333 m = radius
</span>
the area beneath an arc:
Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h²<span> ).
</span>
r² = (11.333 m)² = 128.444 m²
r - h= 11.333 m - 6 m = 5.333 m
r * h = 11.333 m x 6 m = 68 m²
Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ]
Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ]
Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m
Area = 138.828 m² - 53.333 m²
Area = 85.4 m<span>²
</span>
Hope this Helps! Have A Wonderful Day! :)
And as Always...