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2 years ago

If the value of y varies directly with x when y=50, x=4. What is the value of y when x=2

Mathematics

1 answer:

den301095 [7]2 years ago

8 0

Answer:

Step-by-step explanation:

The general equation for a direct variation is y = k*x

So your first step (usually) is to find k

y = k x

when x = 4

then y = 50

y = k*x
50 = k * 4 Divide by 4
50 / 4 = k*4/4
12.5 = k

Now you can find the value of y when x = 2

y = k*x
k = 12.5
x = 2
y = ?

y = 12.5 * 2

y = 25

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3 years ago

Solve the equation 6x + 3y = 15 for y. What does y equal if x = 2? If x = 5?

horsena [70]

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2 years ago

Read 2 more answers

A chemist is using 342 milliliters of a solution of acid and water. If 14.4% of the solution is acid, how many milliliters of ac

Irina-Kira [14]

Answer:

47.88milliliters

Step-by-step explanation:

Given data

Total amount of the solution= 342 milliliters

14% is acid

Hence the amount of acid

=14/100* 342

=0.14* 342

=47.88milliliters

Therefore there are 47.88milliliters of acid

8 0

3 years ago

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

7 0

2 years ago

Sally has 6 boxes of colored pencils only three of the boxes contain 12 colored pencils each .the remaining boxes each contain 2

Sonja [21]

3 times 12 then 3 times 20
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60 + 36 = 96
96 ÷ 8

3 0

2 years ago