g(θ) = 20θ − 5 tan θ
To find out critical points we take first derivative and set it =0
g(θ) = 20θ − 5 tan θ
g'(θ) = 20 − 5 sec^2(θ)
Now we set derivative =0
20 − 5 sec^2(θ)=0
Subtract 20 from both sides
− 5 sec^2(θ)=0 -20
Divide both sides by 5
sec^2(θ)= 4
Take square root on both sides
sec(θ)= -2 and sec(θ)= +2
sec can be written as 1/cos
so sec(θ)= -2 can be written as cos(θ)= -1/2
Using unit circle the value of θ is 
sec(θ)= 2 can be written as cos(θ)=1/2
Using unit circle the value of θ is 
For general solution we add 2npi
So critical points are
Answer: 3 seconds
Step-by-step explanation:
Answer:
$79 total earnings
Step-by-step explanation:
Here, earnings = (hourly rate)(number of hours):
= ($8.30/hr)(6 hrs) + ($7.30/hr)(4 hrs), or
Total earnings = $49.80 + $29.20
" " = $79.00
Answer:the subprime lending giant is a textbook case in creating a corporate culture of denial. ... I oversaw the bank's “secured card” product—a credit card marketed to people ... a 27 percent interest rate and a $39 late fee is better than a payday loan. ... In 2012, the year I started my first Capital One internship, the ...
Step-by-step explanation:
5(-2)^3 5(-2) is -10 to the power of 3 is -1000
