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CaHeK987 [17]
2 years ago
9

Which equation best represents the data? y = –1.026x2 1016.402x – 162075 y = –1.036x2 1024.771x – 163710 y = 298.214x – 66317.66

7 y = 196.2x – 18710
Mathematics
2 answers:
Thepotemich [5.8K]2 years ago
8 0

Answer: person on top is correct

Step-by-step explanation:

it’s A y=-1.026x^2+1016.402x-162075

AleksAgata [21]2 years ago
6 0

The table on the items produced by this company and the profits derived from these goods shows that the best model is y = -1.026x² + 1,016.402x - 162,075.

<h3>Which model best represents the data?</h3><h3 />

Find out the best model by testing all models assuming a given value of x. The model that gives a y value closest to the actual value is the best model.

Assuming x is 100:

= -1.026x² + 1,016.402x - 162,075

= (-1.026 x 100²) + (1,016.402 x 100) - 162,075

= -$70,694.80

Second model:

= -1.036x² + 1024.771x - 163710

= (-1.036 x 100²) + 1024.771 x 100 - 163710

= -$71,593

Third model:

=  298.214x - 66317.667

= 298.214 x 100 - 66317.667

= -$36,496.27

Fourth model:

= 196.2x - 18710

= 196.2 x 100 - 18,710

= $910

The best model is therefore the first model which shows the closest value to the actual y value of -$70,500 when x is 100.

Find out more on fitting models at brainly.com/question/2564940.

#SPJ4

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olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}

Step-by-step explanation:

Original quadratic equation is 9x^{2}-3x-2=0

Divide both sides by 9:

x^{2} - \frac{x}{3} - \frac{2}{9}=0

Add \frac{2}{9} to both sides to get rid of the constant on the LHS

x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}  ==> x^{2} - \frac{x}{3}=\frac{2}{9}

Add \frac{1}{36}  to both sides

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}

This simplifies to

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = \frac{1}{6}\right) we can see that

\left(x - \frac{1}{6}\right)^2 = x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}

So

\left(x - \frac{1}{6}\right)^2=\frac{1}{4}

Taking square roots on both sides

\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}

So the two roots or solutions of the equation are

x - \frac{1}{6}=-\sqrt{\frac{1}{4}}  and x - \frac{1}{6}=\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}} = \frac{1}{2}

So the two roots are

x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}

and

x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}

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