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kykrilka [37]
3 years ago
9

What is the solution of this equation? -1/2n2+18=0

Mathematics
1 answer:
SashulF [63]3 years ago
5 0

Answer:

n=-6\text{ or } n=6

Step-by-step explanation:

So we have the equation:

-\frac{1}{2}n^2+18=0

Subtract 18 from both sides. The left cancels:

-\frac{1}{2}n^2=-18

Multiply both sides by -2. The left cancels again:

n^2=36

Take the square root of both sides:

n=\pm\sqrt{36}

Since we're taking the square root, we need to use plus-minus.

Evaluate:

n=\pm 6

So, the solutions are -6 or 6.

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84,267 nearest thousands
AleksAgata [21]
So the answer would be 84,000. hope that helped
4 0
3 years ago
Read 2 more answers
What is the area of the triangle?<br> 9 4 12
LUCKY_DIMON [66]

Answer:

  13.636

Step-by-step explanation:

The area can be found using Heron's formula:

  A = √(s(s-a)(s-b)(s-c))

where s=(a+b+c)/2.

For the given triangle, ...

  a=9, b=4, c=12, s=(9+4+12)/2 = 12.5

  A = √(12.5(3.5)(8.5)(0.5)) = √185.9375 ≈ 13.636

The area of the triangle is about 13.636 square units.

7 0
3 years ago
Please help( I will give brainliest) <br><br> Thanks
Katen [24]

Answer:

i think it's c.

Step-by-step explanation:

sorry if this is wrong

5 0
3 years ago
Segment CD has point E located on it such that CE:ED = 3:5. If the endpoints are located at C(5, -6) and D(11,18) then what are
wlad13 [49]

Answer:

E(29/4,3)

Step-by-step explanation:

Given that,

Segment CD has point E located on it such that CE:ED = 3:5

The coordinates of C and D are (5, -6) and (11,18) respectively.

We need to find the coordinates of E. Let the coordinates are (x,y). Using section formula to find it as follows :

(x,y)=(\dfrac{m_1x_2+m_2x_1}{m_1+m_2},\dfrac{m_1y_2+m_2y_1}{m_1+m_2})\\\\(x,y)=(\dfrac{3(11)+5(5)}{3+5},\dfrac{3(18)+5(-6)}{3+5})\\\\=\dfrac{29}{4},3

So, the coordinates of E are (29/4,3).

4 0
3 years ago
Sa = 2(pi)(r)(h) + 2(pi)(r^2) v = (pi)(r^2)(h) find the surface area and the volume.
LenKa [72]

If Sa=2πrh+2πr^{2}v=πr^{2}h then the surface area is πr^{2} h and volume is

(rh-2h)/2r.

Given Sa=2πrh+2πr^{2} v=πr^{2}h.

We have to find surface area and volume from the given expression.

Volume is basically amount of substance a container can hold in its capacity.

First we will find the value of v from the expression. Because they are in equal to each other, we can easily find the value of v.

2πrh+2πr^{2}v=πr^{2}h

Keeping the term containing v at left side and take all other to right side.

2πr^{2}v=πr^{2}h-2πrh

v=(πr^{2}h-2πrh)/2πr^{2}

v=πr^{2} h/2πr^{2}-2πrh/2πr^{2}

v=h/2-h/r

v=h(r-2)/2r

Put the value of v in Sa=2πrh+2πr^{2} v

Sa=2πrh+2πr^{2}*h(r-2)/2r

=2πrh+2πrh(r-2)/2

=2πrh+πrh(r-2)

=2πrh+πr^{2}h-2πrh

=πr^{2}h

Hence surface area is πr^{2}h and volume is h(r-2)/2.

Learn more about surface area at brainly.com/question/16519513

#SPJ4

6 0
2 years ago
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