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GalinKa [24]
3 years ago
10

What is the approximate value of √65?

Mathematics
1 answer:
Juliette [100K]3 years ago
6 0
Sq root of 64 =8 so sq root of 65 must be just a little larger than 8
<span>Therefore answer is between 8 & 9

</span>
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A different map has a scale of 1:50000
Deffense [45]

Answer:

8 Km

Step-by-step explanation:

16 x 50000 = 800,000 cm

800,000 cm = 8,000 m

8,000 m = 8 km

I hope this helps, if not sorry

6 0
3 years ago
Please answer correctly !!!!!!!!!!! Will mark brainliest !!!!!!!!!!!
nikklg [1K]

Answer:

lower price = 3

higher price =11

Step-by-step explanation:

p(x) = -2(x-3) (x-11)

Setting equal to zero

0 =  -2(x-3) (x-11)

Using the zero product property

x-3 = 0   x-11 =0

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4 years ago
Find the length of the arc (AB) Leave your answer in terms of Pi
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Delvig [45]

Answer:

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3 0
3 years ago
Which of the following is an improper integral?
guapka [62]

Answer:

A)  \displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx

General Formulas and Concepts:

<u>Calculus</u>

Discontinuities

  • Removable (Hole)
  • Jump
  • Infinite (Asymptote)

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C
  • Improper Integrals

Step-by-step explanation:

Let's define our answer choices:

A)  \displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx

B)  \displaystyle \int\limits^3_1 {\frac{x + 1}{3x - 2}} \, dx

C)  \displaystyle \int\limits^0_{-1} {\frac{x + 1}{3x - 2}} \, dx

D) None of these

We can see that we would have a infinite discontinuity if x = 2/3, as it would make the denominator 0 and we cannot divide by 0. Therefore, any interval that includes the value 2/3 would have to be rewritten and evaluated as an improper integral.

Of all the answer choices, we can see that A's bounds of integration (interval) includes x = 2/3.

∴ our answer is A.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Integration

Book: College Calculus 10e

6 0
3 years ago
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