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Alex777 [14]
3 years ago
9

El perímetro es 28cm y el ancho es de 6 cm cuál es al alto

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
5 0

Answer:

El mayor lado del rectángulo es de 10 cm

Explicación paso a paso:

Perímetro de un rectángulo: es el doble de la suma de sus lados

P = 2 (a+b)

a: es el ancho del rectángulo

b: es el largo del rectángulo

Uno de los lados es 6cm mas que el otro lado

b= a + 6 cm

Sustituimos en la ecuación de perímetro:

28cm /2 = a+a+6cm

14cm = 2a +6 cm

14cm-6cm = 2a

a = 4 cm

b = 10cm

El mayor lado del rectángulo es de 10 cm

brainly.lat/tarea/2483694

Step-by-step explanation:

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Expand the given power by using Pascal’s triangle. (9a - 10b)^6
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Answer:

531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

Step-by-step explanation:

                     1                                n=0

                  1      1                            n=1

                 1   2   1                           n=2

                1  3  3  1                          n=3

              1  4  6  4   1                      n=4

             1  5 10 10 5  1                    n=5

           1 6 15 20 15 6 1                   n=6

This is where n is the exponent in

(x+y)^n.

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

Now we want to expand:

(9a-10b)^6 or we we can rewrite as (9a+(-10b))^6.

Let's replace x with (9a) and y with (-10b) in the expansion:

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

((9a)+(-10b))^6

=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6

Let's simplify a bit:

=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6

=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

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4 years ago
PLEASE SHOW WORK
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(C)

Step-by-step explanation:

The volume of the conical pile is given by

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Taking the derivative of V with respect to time, we get

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Therefore, net worth of Rachel is $ 363587.

Hence, this is the required solution.

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