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Arada [10]
2 years ago
8

Is it a b c or d ? please help i’m doing iready testing

Mathematics
1 answer:
MAXImum [283]2 years ago
5 0

Answer:

the bottom left

Step-by-step explanation:

if it is right brainliest pls

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The Nellie Mae organization conducts an extensive annual study of credit card usage by college students. For their 2004 study, t
Masja [62]

Answer:

1. Null Hypothesis, H_0 : p_1-p_2=0  or  p_1=p_2  

  Alternate Hypothesis<u>,</u> H_A : p_1-p_2\neq 0  or  p_1\neq p_2

2. Test statistics = 4.63

    P-value = 0.00001

3. We conclude that the proportion of undergraduate students who held a credit card differed between these two years.

Step-by-step explanation:

We are given that the Nellie Mae organization conducts an extensive annual study of credit card usage by college students.

For their 2004 study, they analyzed credit bureau data for a random sample of 1,413 undergraduate students between the ages of 18 and 24. They found that 76% of the students sampled held a credit card. Three years earlier they had found that 83% of undergraduates sampled held a credit card.

<em>Let  </em>p_1<em> = population proportion of undergraduate students who held a credit card in year 2001</em>

<em />p_2<em> = population proportion of undergraduate students who held a credit card in year 2004</em>

1. <u>Null Hypothesis</u>, H_0 : p_1-p_2=0  or  p_1=p_2   {means that the proportion of undergraduate students who held a credit card does not differed between these two years}

<u>Alternate Hypothesis,</u> H_A : p_1-p_2\neq 0  or  p_1\neq p_2   {means that the proportion of undergraduate students who held a credit card differed between these two years}

The test statistics that will be used here is <u>Two-sample z proportion statistics</u>;

                        T.S.  = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of undergraduate students who held a credit card in 2001 = 83%

\hat p_2 = sample proportion of undergraduate students who held a credit card in 2004 = 76%

n_1 = sample of students surveyed in 2001 = 1,413

n_2 = sample of students surveyed in 2004 = 1,413

So, <em><u>test statistics</u></em>  =   \frac{(0.83-0.76)-(0)}{\sqrt{\frac{0.83(1-0.83)}{1,413} +\frac{0.76(1-0.76)}{1,413}} }  

                               =  4.63

2. <u><em>Hence, the value of test statistics is 4.63.</em></u>

Also, P-value is given by the following formula;

         P-value = P(Z > 4.63) = 1 - P(Z \leq 4.63)

                                             = 1 - 0.99999 = <u>0.00001</u>

<em />

3. <em>Since in the question we are not given the level of significance so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test. Since our test statistics is does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the proportion of undergraduate students who held a credit card differed between these two years.

6 0
3 years ago
What is the decimal equivalent of ⅞? *<br> 4 points<br> 0.780<br> 0.870<br> 0.875<br> 0.885
Lubov Fominskaja [6]

Answer: 0.875

Step-by-step explanation:  How I got this answer is I used Division, (7 ÷ 8= 0.875)

Hope this helps, Have a great day/night!

~IFoundJiminsLostJams~

4 0
3 years ago
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Calculate the total surface area of a cuboid with the following dimensions. 4m by 6m by 8m​
bonufazy [111]

Answer:

V = 192 m^3

Step-by-step explanation:

The volume of a cuboid is given by

V = l*w*h

V = 4m * 6m *8m

V = 192 m^3

6 0
2 years ago
Hey can someone tell me what -3x^2(14x^2-2x-8) equals
Ad libitum [116K]

Answer:

-42x^4 + 6x^3 + 24x^2

Step-by-step explanation:

8 0
3 years ago
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What is the monthly finance charge if the average daily balance is $2831.83 and the monthly periodic rate is 1.259%?
Kazeer [188]
The answer will 8.00% because you mutuality the both numbers given <span />
3 0
3 years ago
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