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aniked [119]
2 years ago
13

What is the equation of the line that is parallel to the line 5x 2y = 12 and passes through the point (−2, 4)? y = – five-halves

x – 1 y = – five-halvesx 5 y = two-fifthsx – 1 y = two-fifthsx 5
Mathematics
1 answer:
Oduvanchick [21]2 years ago
8 0

Answer:

The answer is

y =  -  \frac{5}{2} x - 1

Step-by-step explanation:

If two equations are parallel it means that both their gradients are equal. We were given the equation:

5x +  2y = 12

in order to find the gradient of this equation that we are given we have to ensure that it is in its simplest form:

5x + 2y = 12 \\ 2y = 12 - 5x \\  \frac{2y}{2}  =  \frac{12}{2}  -  \frac{5}{2} x \\ y = 6  -  \frac{5}{2} x \: \\ or \: \\ y =   - \frac{5}{2} x + 6

Therefore the gradient of the parallel line with points (-2, 4) is also -5/2

y = mx + c \\ 4 =  - \frac{ 5}{2} ( - 2) + c \\ 4 =  \frac{10}{2}   + c \\ 4 = 5 + c \\ 4 - 5 = c \\

c =  - 1 \\ hence \: the \: equation \: for \: the \: \\  parallel \: line \: is \\  \: y =  -  \frac{5}{2} x  - 1

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A right triangular prism has a height of 3 ft, a width of 4 ft, and a hypotenuse of 5 ft. The depth of the triangle is missing.
DiKsa [7]
Depth=15
x=(height(h)*width(w)*hypotenuse(y))/2
x=(3*4*5)/2=(60/2)=30
y=(x(x-h)(x-w)(x-y))^(1/2)
f=(-h^4+2(hw)^2+2(wy)^2-w^4+2(hy)^2-y^4)^(1/2)
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3 years ago
What is the perimeter of triangle DEF
LuckyWell [14K]
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SO basically you just add 3 + 3 = (The side F_E, which you can get by putting numbers in the formula), you should get your answer.

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A force of 60 N is used to stretch two springs that are initially the same length. Spring A has a spring constant of 4 N/m, and
goblinko [34]

Answer:

D:Spring A is 3 m longer than spring B because 15 – 12 = 3.

Step-by-step explanation:

In this question, you should remember the Hooke's Law in physics.

The Hooke's Law simply explains that the extension that occurs on a spring is directly proportional to the load applied on it.

The mathematical expression for this law is

F=-kx

where;

F= force applied on the spring

x = the extension on the spring

k= the spring constant which varies in spring.

The question will need you to calculate the extension on the springs A and B then compare the values obtained.

<u>In spring A</u>

Force, F=60N and spring constant ,k=4 N/m

To find the extension x apply the expression;

F=-kx\\\\60=-4*x\\\\60=-4x\\\\\frac{60}{-4} =\frac{-4x}{-4} \\\\\\-15=x

Here the spring extension is 15 m

<u>In spring B</u>

Force, F=60N and spring constant , k=5N/m

To find the extension x apply the same expression

F=-kx\\\\60=-5*x\\\\60=-5x\\\\\\\frac{60}{-5} =\frac{-5x}{-5} \\\\\\-12=x

Here the extension on the spring is 12 m

<u>Compare</u>

The extension on spring A is 3 m longer than that in spring B because when you subtract the value of spring B from that in spring A you get 3m

=15m-12m=3m

5 0
3 years ago
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