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3 years ago

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Help is very much appreciated!

1 answer:

mote1985 [20]3 years ago

6 0

Answer:

Step-by-step explanation:

nn

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Please help!<br><br> 7.5 in = ________ cm

Naya [18.7K]

The answer is 18 cm because 2.4 cm is in 1 inch. you must multiply 7.5 by 2.4 and get 18

3 0

4 years ago

Read 2 more answers

Una botella tenía agua hasta de su capacidad. Luego, se agregó litro de agua y la botella quedó llena. Si x representa la capaci

Elena L [17]

Responder:

3 / 4x + 1/2 = x

Explicación paso a paso:

Dado que:

Capacidad total = x

Volumen inicial = cierta fracción * capacidad total

Volumen adicional agregado para llenar = 1/2

Por eso,

Inicial. Volumen + volumen adicional = volumen total

De las opciones:

Un volumen inicial de 3 / 4x

Volumen adicional de 1/2

Volumen total = x

Sumar todo hace que la ecuación:

3 / 4x + 1/2 = x

x - 3 / 4x = 1/2

Por lo tanto, la ecuación correcta de la opción es: 3 / 4x + 1/2 = x

7 0

3 years ago

4. Steve has a card collection. He keeps 12 of the cards in a pocket, which

BabaBlast [244]

Answer:

I think 80

Step-by-step explanation:

100/15=6.66666667

12x6.67=80.4

4 0

3 years ago

Find the equation of the line passing through the point (2,-4) that is parallel to the line y=3x+2

m_a_m_a [10]

Answer:

y=3x-10

Step-by-step explanation:

When you have to find a parallel line, you take the slope of the other line, so we already know y=3x+b. Then, plug in 2 and -4 as your x and y values and you get -4=3(2)+b. Then solve 3×2=6, so -4=6+b, subtract 6 from both sides, -10=b.

7 0

3 years ago

The following results come from two independent random samples taken of two populations.

photoshop1234 [79]

Answer:

$(a)\ \bar x_1 - \bar x_2 = 2.0$

$(b)\ CI =(1.0542,2.9458)$

$(c)\ CI = (0.8730,2.1270)$

Step-by-step explanation:

Given

$n_1 = 60$ $n_2 = 35$

$\bar x_1 = 13.6$ $\bar x_2 = 11.6$

$\sigma_1 = 2.1$ $\sigma_2 = 3$

Solving (a): Point estimate of difference of mean

This is calculated as: $\bar x_1 - \bar x_2$

$\bar x_1 - \bar x_2 = 13.6 - 11.6$

$\bar x_1 - \bar x_2 = 2.0$

Solving (b): 90% confidence interval

We have:

$c = 90\%$

$c = 0.90$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.90$

$\alpha = 0.10$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.10/2}$

$z_{\alpha/2} = z_{0.05}$

The z score is:

$z_{\alpha/2} = z_{0.05} =1.645$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.645 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.645 * \sqrt{0.3306}$

$2.0 \± 0.9458$

Split

$(2.0 - 0.9458) \to (2.0 + 0.9458)$

$(1.0542) \to (2.9458)$

Hence, the 90% confidence interval is:

$CI =(1.0542,2.9458)$

Solving (c): 95% confidence interval

We have:

$c = 95\%$

$c = 0.95$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.95$

$\alpha = 0.05$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.05/2}$

$z_{\alpha/2} = z_{0.025}$

The z score is:

$z_{\alpha/2} = z_{0.025} =1.96$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.96 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.96* \sqrt{0.3306}$

$2.0 \± 1.1270$

Split

$(2.0 - 1.1270) \to (2.0 + 1.1270)$

$(0.8730) \to (2.1270)$

Hence, the 95% confidence interval is:

$CI = (0.8730,2.1270)$

8 0

3 years ago