Help is very much appreciated!

Which is larger 946mm or 1 m

aalyn [17]

1 meter. A meter i a thousand millimeters

6 0

3 years ago

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Which statement best describes the relationship between the positions of the two players

Lena [83]

Answer:

N is M reflected across the x-axis; only the signs of the x-coordinates of M and N are different.

Step-by-step explanation:

The y-axis is vertical, and the x-axis is horizontal. If a point, or image, is reflected over the x-axis, in this case M and N, then the signs of the y-coordinates do not change, and instead the coordinates of the x-axis change.

7 0

3 years ago

5x-3=13-3x(if there is no solution,type in ''no solution'') x= Answer

Sati [7]

Answer:

2

just solve it and it will come out

8 0

3 years ago

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Factor *<br> (x^2/9)- 64

Hoochie [10]

Step-by-step explanation:

We use

$a ^{2} - \times ^{2} = (a - \times )(a + \times )$

Now we have

$\frac{ { \times }^{2} }{9} - 64 = ( \frac{ \times }{3} ) ^{2} - {8}^{2} \\ = ( \frac{ \times }{3} - 8)( \frac{ \times }{3} + 8)$

Hope that useful for you

5 0

3 years ago

Please help I will give Brainliest please!

WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but $x \ne 0$ </h3>

To write this in interval notation, we can say $(-\infty, 0) \cup (0, \infty)$ which is the result of poking a hole at 0 on the real number line.

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The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say $(-\infty, \infty)$ which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

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Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation $x = \pm 4$

These are the locations where the blue hyperbolic curve crosses the x axis.

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Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

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Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

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Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer: Oblique asymptote is y = 3x</h3>

5 0

2 years ago