36 and 48
a = b+12
a+b = 84
(b+12) + b =84
2b +12 = 84
2b = 72
b= 36
a = b + 12
a = 36 + 12
a = 48
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
Answer:
12 flips
Step-by-step explanation:
Answer: s = -4
Step-by-step explanation:
s/4 + 15 = 14
We can subtract 15 from both sides:
s/4 = -1
We can multiply both sides by 4:
s = -4
A cause you just gotta think about it and realize you got it