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Simora [160]
2 years ago
8

Which expression is equivalent to 144 superscript three-halves?

Mathematics
2 answers:
IrinaK [193]2 years ago
8 0

Using the law of indices the equivalent expression of 144^{\frac{3}{2} } is 1728

<h3>How to find equivalent expression?</h3>

The equivalent expression of 144^{\frac{3}{2} } can be express as follows:

Using the law of indices,

(a^{b} )^{c}  = a^{bc}

Applying this laws,

144^{\frac{3}{2} }=(12^{2} )^{\frac{3}{2} }

Hence,

144^{\frac{3}{2} }=(12^{2} )^{\frac{3}{2} } = 12^{3}

Finally,

12³ = 1728

learn more on expression here: brainly.com/question/16619965

#SPJ4

pantera1 [17]2 years ago
5 0

The expression that is equivalent to 144 superscript three-halves (144^{\frac{3}{2} } ) is 1728

<h3>Evaluation of expression</h3>

From the question, we are to determine the expression which is equivalent to 144 superscript three-halves

The given expression is

144^{\frac{3}{2} }

This can be simplified as shown below

144^{\frac{3}{2} }

(12^{2} )^{\frac{3}{2} }

This becomes

12^{2 \times \frac{3}{2} }

12^{3}

= 1728

Hence, the expression that is equivalent to 144 superscript three-halves (144^{\frac{3}{2} } ) is 1728.

Learn more on Evaluating an expression here: brainly.com/question/25896085

#SPJ4

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Find the 13th term of the arithmetic sequence -3x – 1,42 + 4,112 + 9, ...
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Answer:

The 13th term is 81<em>x</em> + 59.

Step-by-step explanation:

We are given the arithmetic sequence:

\displaystle -3x -1, \, 4x +4, \, 11x  + 9 \dots

And we want to find the 13th term.

Recall that for an arithmetic sequence, each subsequent term only differ by a common difference <em>d</em>. In other words:

\displaystyle \underbrace{-3x - 1}_{x_1} + d = \underbrace{4x + 4} _ {x_2}

Find the common difference by subtracting the first term from the second:

d = (4x+4) - (-3x - 1)

Distribute:

d = (4x + 4) + (3x + 1)

Combine like terms. Hence:

d = 7x + 5

The common difference is (7<em>x</em> + 5).

To find the 13th term, we can write a direct formula. The direct formula for an arithmetic sequence has the form:

\displaystyle x_n = a + d(n-1)

Where <em>a</em> is the initial term and <em>d</em> is the common difference.

The initial term is (-3<em>x</em> - 1) and the common difference is (7<em>x</em> + 5). Hence:

\displaystyle x_n = (-3x - 1) + (7x+5)(n-1)

To find the 13th term, let <em>n</em> = 13. Hence:

\displaystyle x_{13} = (-3x - 1) + (7x + 5)((13)-1)

Simplify:

\displaystyle \begin{aligned}x_{13} &= (-3x-1) + (7x+5)(12) \\ &= (-3x - 1) +(84x + 60) \\ &= 81x + 59 \end{aligned}

The 13th term is 81<em>x</em> + 59.

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spin [16.1K]

Answer:

(+2)(+6)

Step-by-step explanation:

2+8+12

:) Hope this helped

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