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sdas [7]
3 years ago
7

What is the sum of 3/4 and 4/5?​

Mathematics
2 answers:
egoroff_w [7]3 years ago
5 0

Answer:

Hi, There!

Thanks for choosing Brainly!

<h2>Question</h2>

what is the sum of 3/4 and 4/5?​

<h2>Answer</h2>

1\frac{11}{20}

Step-by-step explanation:

\frac{3}{4} +\frac{4}{5}  = ?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(3/4, 4/5) = 20

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(\frac{3}{4~} x~\frac{5}{5} )+ (\frac{4}{5} ~x~\frac{4}{4}) = ?

Complete the multiplication and the equation becomes

\frac{15}{20} +\frac{16}{20}  = ?

The two fractions now have like denominators so you can add the numerators.

Then:

15 + 16 = 31

20  =    20

\frac{31}{20} is the same as  31 ÷ 20

Convert to a mixed number using

long division for 31 ÷ 20 = 1R11, so

The Answer is 1\frac{11}{20}

dybincka [34]3 years ago
3 0

Answer:

your answer is 1.5

Step-by-step explanation:

3/4 simpified is 0.75 + 4/5 simplied is 0.8

0.75+0.8=1.5

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Hi there!

The general formula of A line in slope-intercept form is the following:
y = mx + n

In this formula m represents the slope of the line. Therefore, we can conclude that m = 2/5.
y =  \frac{2}{5} x + n

We also know that the line passes through the point (-3, -1) and we can therefore substitute this coordinate into the formula of the line.
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Multiply first.
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And finally add 1 1/5 to both sides of the equation.
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Step-by-step explanation:

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Step-by-step explanation:

<em>Given</em>

<em>We </em><em>know </em><em>that </em><em>in </em><em>a </em><em>parallelogram </em><em>opposite </em><em>angles </em><em>are </em><em>equal</em><em>. </em><em>So </em>

<em>1st </em><em>and </em><em>3rd </em><em>angles </em><em>=</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em>

<em>Let </em><em>2nd </em><em>and </em><em>4th </em><em>angles </em><em>=</em><em> </em><em>x</em>

<em>Now</em>

<em>1</em><em>1</em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>x </em><em>+</em><em> </em><em>x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em><em> </em><em>(</em><em> </em><em>Being </em><em>sum </em><em>of </em><em>angles </em><em>of </em><em>parallelogram</em><em>) </em>

<em>2</em><em>3</em><em>6</em><em>°</em><em> </em><em>+</em><em> </em><em>2x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em>

<em>2x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em><em> </em><em>-</em><em> </em><em>2</em><em>3</em><em>6</em><em>°</em>

<em>2x </em><em>=</em><em> </em><em>1</em><em>2</em><em>4</em><em>°</em>

<em>Therefore </em><em>x </em><em>=</em><em> </em><em>6</em><em>2</em><em>°</em>

<em>Now </em><em>the </em><em>measure </em><em>of </em><em>other </em><em>all </em><em>angles </em>

<em>118</em><em>°</em><em> </em><em>,</em><em> </em><em>6</em><em>2</em><em>°</em><em> </em><em>,</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em><em>,</em><em> </em><em>6</em><em>2</em><em>°</em>

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3 years ago
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