Please Help me someone! I dont even know where to start. Solve for X
1 answer:
There is actually a cool trick to this. When you see a and 2a, in this case 6 and 12, then the small triangle is a 60-30-90 triangle. The remaining side is 
.
This value rounds down to 10, and yep, you guessed it, another 30-60-90.
This time, x =
.
This is a very difficult problem and requires knowledge of the special triangles. Hope this helps!
This value rounds down to 10, and yep, you guessed it, another 30-60-90.
This time, x =
This is a very difficult problem and requires knowledge of the special triangles. Hope this helps!
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Answer:
The degrees of freedom first given by:
Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:
And for this case the rejection region would be:
b) Reject H0 if tcalc >1.7960
Step-by-step explanation:
Information given
5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.
System of hypothesis
We want to test if the true mean is higher than 5, the system of hypothesis are :
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
The degrees of freedom first given by:
Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:
And for this case the rejection region would be:
b) Reject H0 if tcalc >1.7960