Answer:
<u>Solutions given;</u>
<u>Using cosine rule</u>
b²=a²+c²-2*a*c*cos B°
b²=15²+8²-2*15*8*cos39
b²=102.48
b=
b=10.12
b=10.1
<u>Using sine rule</u>


<u>Doing criss cross multiplication</u>
Sin C=
m<C=Sin -¹(0.29)
m<C=14.98
<u>m<C=15°</u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
11 a. Since she runs 10km in one hour she runs 5km in half an hour and 25km in 2 and a half hours
11b. Since she runs 5 miles in one hour she runs 2.5 miles in half an hour and 12.5 mils in 2 and a half hours
11 c. Since 1.60934 kilometers = 1 mile, Clair ran the farther distance
12 a. 13.20/6 = 2.2 dollars for 1 bowl
12 b. 9/3 = 3 and if he got 3 sets of 3 free bowls he bought 24 pairs of glasses
12 c. If Malcom bought 24 pairs of glasses 24*1.80 = 43.2, so he spent 43.2 dollars on glasses
13 a. 6 to 4 or 6:4
Jacob wants to build a rectangular enclosure for his animals. One side of the pen will be against the barn,so he needs no fence on that side.
Let w be the width of the enclosure (perpendicular to the barn) and let l be the length of the enclosure (parallel to the barn).
one side of the length is not counted for perimeter because one side of length will be against the barn.
Perimeter = 400 ft
Perimeter of rectangle = L + W + W
400 = L + 2W
L = 400 - 2W
Area = L * W
Replace L by 400 - 2W
A(W) = (400 - 2W) * W

Now we find out x coordinate of vertex to find the width that maximize the area

a= -2 and b = 400

The width w would maximize the area is w = 100ft
To find maximum area we plug in 100 for W in A(W)


the maximum area is 20,000 square feet
The answer is 2.25h when we do theese equation
95-50=45
45/20=2.25h