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Helga [31]
2 years ago
14

Each day Diego's mother drives to her office in Baltimore. The driving distance from home to Baltimore, Maryland is 7 miles. On

her way home, she runs some errands at the mall so her driving distance is 8 miles How many miles does his mother drive going to work and coming home for 3 days?
Select the expression that represents the problem above

a) 7 + 8 + 3
b) (7 + 3) x 8
c) (7 + 8) = 3
d) (7 + 8) X3​
Mathematics
1 answer:
Sidana [21]2 years ago
6 0

Answer:

D

Step-by-step explanation:

(7+8)*3

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Madeline invested $51,000 in an account paying interest rate of 6 1/8% compounded daily. Harper invested 51000 in an account pay
LenaWriter [7]

Answer:

$5564.87

Step-by-step explanation:

We are to determine the difference between the future values of each investment

The formula for calculating future value:

FV = P (1 + r)^mn

FV = Future value  

P = Present value  

R = interest rate  

N = number of years

m = number of compounding

Madeline

P = Present value = 51,000

R = interest rate = 0.06125 / 365 = 0.000168

N = number of years = 13

m = number of compounding = 365

51,000 x (1.000168)^4745  = 113,070.20

Harper

51,000 x (1.004792)^156 = 107,505.33

Difference = 113,070.20 - 107,505.33 = $5,564.87

6 0
2 years ago
Read 2 more answers
CAN SOMEONE GOOD AT MATH HELP PLEEESE!!
Rufina [12.5K]

Answer: 1 .Thus for a graph to have an Euler circuit, all vertices must have even degree. The converse is also true: if all the vertices of a graph have even degree, then the graph has an Euler circuit, and if there are exactly two vertices with odd degree, the graph has an Euler path.

2. A graph has an Euler circuit if and only if the degree of every vertex is even. A graph has an Euler path if and only if there are at most two vertices with odd degree.

Step-by-step explanation:

Can i have branily plz

7 0
2 years ago
Is (2, 3) a solution to this system of equations?<br> 2x + y = 7<br> 17x + 19y = 18<br> yes<br> no
netineya [11]

I think its not a correct solution of given equations.

4 0
3 years ago
Solve for x:−2(x+9)=−1(x+−1)+2
Stella [2.4K]

Answer:

A

Step-by-step explanation:

expanding the bracket, we would have

-2x -18 = -x+1+2

-2x+x= 3 +18

-x=21

x=-21

6 0
3 years ago
Read 2 more answers
Given the function f(x) = x^4 + 3x^3 - 2x^2 - 6x - 1, use intermediate theorem to decide which of the following intervals contai
marta [7]

f(x) = x^4 + 3x^3 - 2x^2 - 6x - 1

Lets check with every option

(a) [-4,-3]

We plug in -4  for x  and -3 for x

f(-4) = (-4)^4 + 3(-4)^3 - 2(-4)^2 - 6(-4) - 1= 55

f(-3) = (-3)^4 + 3(-3)^3 - 2(-3)^2 - 6(-3) - 1= -1

f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.

(b) [-3,-2]

We plug in -3  for x  and -2 for x

f(-3) = (-3)^4 + 3(-3)^3 - 2(-3)^2 - 6(-3) - 1= -1

f(-2) = (-2)^4 + 3(-2)^3 - 2(-2)^2 - 6(-2) - 1= -5

f(-2) is negative and f(-3) is negative. there is no value at x=c on the interval [-3,-2] where f(c)=0.  

(c) [-2,-1]

We plug in -2  for x  and -1 for x

f(-2) = (-2)^4 + 3(-2)^3 - 2(-2)^2 - 6(-2) - 1= -5

f(-1) = (-1)^4 + 3(-1)^3 - 2(-1)^2 - 6(-1) - 1= 1

f(-2) is negative and f(-1) is positive. there is some value at x=c on the interval [-2,-1] where f(c)=0. so there exists atleast one zero on this interval.

(d) [-1,0]

We plug in -1  for x  and 0 for x

f(-1) = (-1)^4 + 3(-1)^3 - 2(-1)^2 - 6(-1) - 1= 1

f(0) = (0)^4 + 3(0)^3 - 2(0)^2 - 6(0) - 1= -1

f(-1) is positive and f(0) is negative. there is some value at x=c on the interval [-1,0] where f(c)=0. so there exists atleast one zero on this interval.

(e) [0,1]

We plug in 0  for x  and 1 for x

f(0) = (0)^4 + 3(0)^3 - 2(0)^2 - 6(0) - 1= -1

f(1) = (1)^4 + 3(1)^3 - 2(1)^2 - 6(1) - 1= -5

f(0) is negative and f(1) is negative. there is no value at x=c on the interval [0,1] where f(c)=0.  

(f) [1,2]

We plug in 1  for x  and 2 for x

f(1) = (1)^4 + 3(1)^3 - 2(1)^2 - 6(1) - 1= -5

f(2) = (2)^4 + 3(2)^3 - 2(2)^2 - 6(2) - 1= 19

f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.

so answers are (a) [-4,-3], (c) [-2,-1],  (d) [-1,0], (f) [1,2]

8 0
3 years ago
Read 2 more answers
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