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Oliga [24]
2 years ago
13

The figure is cut into 15 equal pieces. Shade 2/3 of the figure.

Mathematics
1 answer:
Anna007 [38]2 years ago
7 0

Answer:

Shade 10 of the pieces.

Step-by-step explanation:

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Instructions:select all the correct locations on the tables. andrew wants to purchase a new television with a screen length that
DaniilM [7]

The <em>correct answers</em> are:


5x²+70x+245 ≥ 1050; and

Yes.


Explanation:


Let x be the width of the tablet. Since the width of the TV is 7 inches more than the tablet, the width of the TV would be x+7.


The length of the TV is 5 times the width; this makes the length 5(x+7) = 5x+35.


The area of the TV would be given by

(x+7)(5x+35).


Since Andrew wants the area to be at least 1050, we set the expression greater than or equal to 1050:

(x+7)(5x+35) ≥ 1050


Multiplying this, we have:

x*5x+x*35+7*5x+7*35 ≥ 1050

5x²+35x+35x+245 ≥ 1050


Combining like terms,

5x²+70x+245 ≥ 1050


To see if 8 is a reasonable width for the tablet, we substitute 8 for x:

5(8²)+70(8)+245 ≥ 1050

5(64)+560+245 ≥ 1050

320+560+245 ≥ 1050

1125 ≥ 1050


Since this inequality is true, 8 is a reasonable width.

5 0
3 years ago
Help me with this if anyone can! Please and thank you
Valentin [98]

ANSWER

y = 3x - 3

EXPLANATION

Let

y = mx + c

be the equation.

We can choose any two ordered pairs to determine the equation of the relation.

(6,15) \: and \:  (8,21)

We find m using the formula;

m =  \frac{y_2-y_1}{x_2-x_1}

m =  \frac{21 - 15}{8 - 6}  =  \frac{6}{2}  = 3

The equation becomes

y = 3x + c

When x=6, y=15.

This implies that,

15 = 3(6) + c

15= 18 + c

15 - 18= c

c =  -3

The equation of the relation is therefore,

y = 3x -3

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4 years ago
6÷x (1+2)=1 please tell me how to work this out
Vinvika [58]
First of all 1+2=3 which leads to 6:3x=1 3x=6:1 3x=6 X=2
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Determine whether the following statement is true or false. If false, provide a counterexample. If two events are independent, t
Jet001 [13]

Answer:

TRue

Step-by-step explanation:

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What do you call it when 50 people stand on a wooden dock
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